D. The combined expenses In Year 3 and 4 were $300,000 more than the combined of Year 3 and 4
4x - 3y + 20 = 0....4x - 3y = -21
4x - 3y = -21.....multiply by -2
5x - 6y = -25
----------------
-8x + 6y = 42 (result of multiplying by -2)
5x - 6y = -25
---------------add
-3x = 17
x = -17/3
this system of equations has 1 solution
Answer:
The largest possible area of the deck is 87.11 m² with dimensions;
Width = 9.33 m
Breadth = 9.33 m
Step-by-step explanation:
The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square
Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area
The length of the given railing = 28 m
The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each
The area of a square of side s = s²
The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;
Width = 28/3 m = 9.33 m
Breadth = 28/3 m = 9.33 m.
I believe it is negative 2/2, hope this helps you out.
Answer:
The equation of the line in the slope-intercept form is y = -5x + 79
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
- m is the slope of the line
- b is the y-intercept
∵ The slope of the line is -5
∴ m = -5
∵ The form of the equation is y = m x + b
→ Substitute the values of m in the form of the equation
∴ y = -5x + b
→ To find b substitute x and y in the equation by the coordinates
of any point on the line
∵ The line passes through the point (18, -11)
∴ x = 18 and y = -11
∵ -11 = -5(18) + b
∴ -11 = -90 + b
→ Add 90 to both sides to find b
∵ -11 + 90 = -90 + 90 + b
∴ 79 = b
→ Substitute it in the equation
∴ y = -5x + 79
∴ The equation of the line in the slope-intercept form is y = -5x + 79
