Answer:
The highest speed measured was 78.2 Mbps.
n = 50
a)What is the difference between carrier's highest data speed and the mean of all 50 data speeds?
= 78.2 - 18.22
=59.98
b)How many standard deviations is that [the difference found in part (a)]
=
c) Convert the carrier's highest data speed to a z score.
d) If we consider data speeds that convert to z scores between minus2 and 2 to be neither significantly low nor significantly high
Yes the carrier's highest data speed is significant because it is greater than 2.
Answer:
it is 2 bcz if we see that in the 12 , 18 and 56 the two is the highest common factor
Answer:
B
Step-by-step explanation:
The entry A is the result of multiplying - x and 3x, that is
- x × 3x = - 3x² → B
V = (Base Area)(height)
V = (side)^2 * (height)
144 = 4^2 * h
144 = 16*h
h = 144/16
h = 9 cm. [ANSWER]