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Anuta_ua [19.1K]
3 years ago
14

What is the median for this list of numbers? 3, 6, 9, 10, 12

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0
The answer is 9 because if you put those numbers in a life from smallest to biggest and take one off each side your left with 9
faust18 [17]3 years ago
6 0

Answer:

9

Step-by-step explanation:

You might be interested in
What is the answer of this on (if 3 pieces of candy cost $2.10 how much would four pieces cost)
ale4655 [162]

Answer:

70 hope it helps

Step-by-step explanation:

210/3=70

5 0
2 years ago
Find the x-values that are solutions of the equation 5cot^2x-15=0
julia-pushkina [17]
First solve for the trig function 'cot'
cot^2 x = \frac{15}{5} = 3

Next take the sqrt of both sides (include plus/minus)
cot x = \pm \sqrt{3}

Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)

tan x = \pm \frac{1}{\sqrt{3}} = \pm \frac{\sqrt{3}}{3}

Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.

x = \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}
3 0
3 years ago
The seat of a bench is the shape of a Trapezoid with bases of 8 feet and 7 feet and a height on 3.5 feet whats the are of the se
Pepsi [2]

Answer:

26.25 square feet

Step-by-step explanation:

Calculation to determine the area of the seat

Using this formula

Area=1/2*(b1+b2)*h

Where,

b1=8 feet

b2=7 feet

h=3.5 feet

Let plug in the formula

Area=1/2*(8+7)*3.5

Area=1/2*15*3.5

Area=26.25

Therefore the area of the seat is 26.25 square feet

6 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
4 years ago
15 pts and brainliest, true, correct answers only <br><br> If N∈AB and AN= 1 3 · AB, then BN = · AB.
laiz [17]

Answer:

13

Step-by-step explanation:

Not sure, i'm sorry

should be the same logic as

a=b

b=c

a=c

4 0
3 years ago
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