He worked with large numbers of plants.
Given data:
Mass of cesium chloride CsCl (m) = 52.3 g
Mass of water (mh2O)= 60.0 g
Volume of the solution (V) = 63.3 ml
Step 1: Calculate the number of moles of CsCl
Molar mass of CsCl = 168.36 g/mol
Mass of CsCl = 52.3 g
# moles = mass/molar mass = 52.3 g/168.36 g.mol-1 = 0.3106 moles
Step 2: Volume of solution in Liters
1000 ml = 1 liter
therefore, 63.3 ml corresponds to : 63.3 ml * 1 L/1000 ml = 0.0633 L
Step 3: Calculate molarity of CsCl
Molarity = moles of CsCl/volume of solution
= 0.3106 moles/0.0633 L = 4.91 moles/L
Molarity = 4.91 M
we will use the root mean squared speed of oxygen formula
v= (3RT) / M
T= vM/3R
where
v =1.12x104 m/s; velocity
R= (8.31447 kg m2 s-2 K-1 mol-1) gas constant
M = 0.0319988 kg/mol; molar mass of oxygen
substituting the given values, we will get
T(K)= 14.37K or -258.78 C
Oxygen molecules speed of 1.12x104 m/s is at temperature -258.78C.
There can be three mole ratios that can be written involving three substances.It depends on the constant of your reactant to your product. It also depends on the asked mole ratio. But the maximum would be 3 mole ratios because you have 3 substances in your reaction.
