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olya-2409 [2.1K]
3 years ago
6

Can send me the answer plzzz

Chemistry
1 answer:
Len [333]3 years ago
5 0

Answer: In balancing any chemical equations, the number of atoms of each elements on the reactant side is equals to the number of atoms of the elements on the product side.

Explanation:

Balanced Chemical equations are those equations that has the equal number of atoms of elements on both the reactants and the product sides. To ensure that the chemical equations are correctly balanced the following steps should be observed.

--> identify the elements on the reactant side and on the product side

--> identify the number of atoms of each elements.

--> multiply the number of atoms with the number that will give you a coefficient that will make both the reactant and product sides equal.

--> place the new numbers infront of the elements or compounds.

--> A final check is done to know if the equation is balanced.

From the above steps, the balanced equation of the above questions are listed below:

1.) AlBr3 + 3K ---> 3KBr + Al

2.) FeO + PdF2 --> FeF2 + PdO

3.) P4 + 6Br2 --> 4PBr3

4.) 2LiCl + Br2 --> 2LiBr + Cl2

5.) PbBr2 + 2HCl --> 2HBr + PbCl2

6.) 2CoBr3 + 3CaSO4 --> 3CaBr2 + Co2(SO4)3

7.) 2Na3P + 3CaF2 --> 6NaF + Ca3P2

8.) 2Mn + 6HI --> 3H2 + 2MnI3

9.) Li3PO4 + 3NaBr --> Na3PO4 + 3LiBr

10.) CaF2 + Li2SO4 --> CaSO4 + 2LiF

11.) 2HBr + Mg(OH)2 --> MgBr2 + 2H2O

12.) 2LiNO3 + CaBr2 --> Ca(NO3)2 + 2LiBr

13.) AgNO3 + Li --> LiNO3 +Ag

14.) Si(OH)4 + 4NaBr --> SiBr4 + 4NaOH

15.) 2NaCN + CuCO3 --> Na2CO3 + Cu(CN)2

16.) 2NH3 + H2SO4 --> (NH4)2SO4

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FrozenT [24]

A small region of a cancer patient’s brain is exposed for 24.0 min to 475 Bq of radioactivity from⁶⁰Co for treatment of a tumor.

<h3>What is tumor?</h3>

The Latin word for swelling is tumor. The term "tumor" is frequently used by laypeople to refer to cancerous growths, while the medical term "neoplasme" (sometimes known as "new-formation") is more appropriate in this context. A tumor can be benign or malignant; the last case is when it is the result of a cancerous growth.

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6 0
2 years ago
The Ksp for Cu(OH)2 is 4.8 × 10-20. Determine the molar solubility of Cu(OH)2 in a buffer solution with a pH of 10.1.
Papessa [141]

Answer:

E) 3.0x10⁻¹²

Explanation:

Ksp of Cu(OH)₂ is defined as:

Cu(OH)₂(s) ⇄ Cu²⁺(aq) + 2 OH⁻(aq)

Ksp = [Cu²⁺] [OH⁻]²

When pH is 10.1,  [OH⁻] is:

pOH = 14 - pH

pOH = 3.9

pOH = -log [OH⁻]

<em>[OH⁻] = 1.26x10⁻⁴M</em>

<em />

Replacing in ksp formula:

4.8x10⁻²⁰= [Cu²⁺] [1.26x10⁻⁴]²

<em>3.0x10⁻¹² = [Cu²⁺] </em>

That means the maximum amount of Cu²⁺ that can be in solution is 3.0x10⁻¹²M, thus, molar solubility of Cu(OH)₂ is

<em>E) 3.0x10⁻¹²</em>

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<span>0.72 mL of solution will have 180 mg of amoxicillin. For this problem, you need to calculate the equivalent ratio of volume as to the ratio of amoxicillin. So 180/500 = X/2.0 Multiply both sides by 2 2 * 180/500 = X 360/500 = X 18/25 = X 0.72 = X So you need 0.72 mL of solution to get 180 mg of the drug.</span>
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