F=ma
390,000=f(9,000)
390,000/9,000= f
43.3333 m/s^2
Answer:
Answer is 72.15 or 0.07215
Explanation:
Given,
Initial molarity M1 = 3.21M
Initial volume V1 = 25.4mL
Final molarity of M2 = 1.13 M
Final volume V2 = ?
M1×V1=M2×V2
M1×V1/M2=V2
3.21M×25.4/1.13=V2
V2=72.15 mL. 1 mL=0.001 L
V2= 0.07215
The mass would also increase by the same amount/rate.
Answer:
1. 9.57 × 10^-9 moles.
2. 7.38mol
Explanation:
1.) To find the number of moles there are in the number of particles in an atom, we divide the number of particles (nA) by Avagadro's constant (6.02 × 10^23)
Hence, to find the number of moles (n) of Manganese (Mn), we say:
5.76 x 10^15 atoms ÷ 6.02 × 10^23
5.76/6.02 × 10^(15-23)
= 0.957 × 10^-8
= 9.57 × 10^-9 moles.
2.) Mole = mass/molar mass
Molar mass of sodium chloride (NaCl) = 23 + 35.5
= 58.5g/mol
mole = 431.6 g ÷ 58.5g/mol
mole = 7.38mol
