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alukav5142 [94]

3 years ago

5

What is the chemical formula of sodium carbonate?

1 answer:

Gekata [30.6K]3 years ago

6 0

Answer:

Na2CO3 is the formula for sodium carbornate

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Which is true about covalent compounds?have a high melting pointconduct electricity when dissolved in waterhave a low boiling po

iris [78.8K]

The correct answer from the choices given is the third option. Covalent compounds have low boiling points. Also, their melting points are low. Covalent bonds have relatively low attractions which results to these properties. The bonds are easily broken by taking energy or adding energy.

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3 years ago

Write the name of any two metalloids ?

sertanlavr [38]

Answer:

Germanium and Polonium

Explanation:

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4 0

3 years ago

Read 2 more answers

I still need a bit of help.

Ostrovityanka [42]

H. The atom would no longer be aluminum
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5 0

3 years ago

If 0.4506 g of KHP standard were titrated with NaOH and the endpoint was reached at 27.96 mL, what is the concentration (molarit

Lemur [1.5K]

Answer is in attachment.

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6 0

3 years ago

In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i

GalinKa [24]

Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: $V_{1}$ = 21.35 mL, $M_{1}$ = 0.150 M

$V_{2}$ = 25.0 mL, $M_{2}$ = ?

Formula used to calculate molarity of $H_{2}SO_{4}$ is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M$

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = $V_{1} + V_{2}$

= 21.35 mL + 25.0 mL

= 46.36 mL (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol$

Thus, we can conclude that there are 0.006 moles of acid in the flask.

3 0

3 years ago