0.3 or 30%. The probability that Ace pick a banana from a basket that content others fruits is 0.3.
The key to solve this problem is using the equation of probability where n(A) the numbers of favorables outcomes and n the numbers of possible outcomes.
There are in the basket 10 fruits in total (3 bananas + 4 apples + 3 oranges = 10fruits). Then, extract a fruit can occur in 10 ways, this is n. There is only 3 bananas in the basket, so the fruit that ACE will pick be a banana can occur in 3 ways out of 10, so 3 is n(A).
Solving the equation:
Answer:
or
Step-by-step explanation:
Answer:
A) 32.474 + 16.577
= 49.051
C) 19.213 + 4.578
= 23.791
Step-by-step explanation:
Place value may be defined as the positional system of a notation where the position of any number with reference to the decimal point determines the value of that number.
A) 32.474 + 16.577
= 49.051
B) 23.452 + 31.561
= 55.013
C) 19.213 + 4.578
= 23.791
D) 8.128 + 9.192
= 17.32
We have to find the expression which contains 1 in the thousandths place in the sum.
We know after the decimal point, the place value are designated as tenths, hundredths, thousandths, and so on.
Therefore, A). 49.051 and C). 23.791 has a place value of 1 in its thousandths place.
X+32 y=32 that’s the answer, just sum it up