Using integration, it is found that the area between the two curves is of 22 square units.
<h3>What is the area between two curves?</h3>
The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:

In this problem, we have that:
.
Hence, the area is:


Applying the Fundamental Theorem of Calculus:


The area between the two curves is of 22 square units.
More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870
48 cubes can be packed into shape
Answer:
They added 8 to each side, --8 is +8 so we need to subtract - from each side not add 8 to each side
Step-by-step explanation:
We have a slope and a point
We can use point slope form
y-y1 = m(x-x1)
y--8 = -6(x-2)
y+8 = -6(x-2)
Distribute the -6
y+8 = -6x+12
Subtract 8 from each side
ERROR in the students work
They added 8 to each side, --8 is +8 so we need to subtract - from each side not add 8 to each side
y+8-8 = -6x+12-8
y = -6x+4
Answer:
x=5
Step-by-step explanation:
To start solving this, you want to solve an equation for y. I chose 3x - 7y = 4 for later purposes. Subtract 3x from both sides and divide by -7 to get y = 4 - 3x / -7. Now because we have a value for y in terms of x, plug this into the other equation, x + 7y = 16. It now should look like this: x + 7(4 - 3x / -7) = 16. Now just distribute the 7 and simplify the denominator to get x+ (-4+3x)=16. This can now be 4x +4 = 16, starting to look familiar now. Lastly subtract the 4 from both sides and divide by 4 to get x = 5. Hope this helps!
0.4 as a fraction would be 2/5 :)