All categories

3 years ago

Help asap please will give brainliest

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

4 0

Answer:

d. (x+2)/(-x²-5)

Step-by-step explanation

ƒ(x) = x + 2/(2x²)

The function is undefined when x = 0.

b. ƒ(x) = (2x + 4)/(3x + 3)

The function is undefined when 3x + 3 = 0, i.e., when x = -1.

c. ƒ(x) = (6x - 5)/(x² - 7)

The function is undefined when x² - 7 = 0, i.e., when x = √7.

d. ƒ(x) = (x+2)/(-x²-5) = -(x+2)/(x² + 5)

The function would be undefined if x² + 5 = 0, i.e., if x² = -5. However, the square of a real number cannot be negative.

This function has no excluded values.

You might be interested in

Natalka [10]

Your answer is $7.50x=90

3 0

3 years ago

What two numbers make on thousand

Igoryamba

Answer:

500 and 500

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Jennifer utilizo 2/7 de metro de cinta para hacer moños para sus primas. Ahora le quedan 10/21 de metro de cinta. ( problema ver

Vikki [24]

Answer:

$x = \frac{16}{21}\,m$

Step-by-step explanation:

El enunciado pregunta la cantidad inicial de cinta utilizada por Jennifer, la cual es la suma de la porción utilizada y la porción remanente:

$x = \frac{2}{7}\,m + \frac{10}{21}\,m$

$x = \frac{42}{147}\,m + \frac{70}{147}\,m$

$x = \frac{112}{147}\,m$

$x = \frac{16}{21}\,m$

6 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

What is the lowest value in the set of data represented by the following box-and-whisker plot?

Sever21 [200]

D.11.5 because when you bring the line and the dot it is 11.5

8 0

3 years ago

Read 2 more answers