Option A
The system of equations are x + y = 40 and 10x + 7y = 360
<em><u>Solution:</u></em>
Let pounds of expensive coffee beans be x
Let pounds of cheaper coffee bean be y
Cost of 1 pound of expensive coffee bean = $ 10
Cost of 1 pound of cheaper coffee bean = $ 7
<em><u>The shop also sells a 40 pound mixture of the two kinds of coffee beans</u></em>
pounds of expensive coffee beans + pounds of cheaper coffee bean = 40
x + y = 40 ------ eqn 1
<em><u>The shop also sells a 40 pound mixture of the two kinds of coffee beans for $9 per pound</u></em>
pounds of expensive coffee beans x Cost of 1 pound of expensive coffee bean + pounds of cheaper coffee bean x Cost of 1 pound of cheaper coffee bean = 40 pound mixture x $ 9
10x + 7y = 360 --------- eqn 2
Thus the system of equations are x + y = 40 and 10x + 7y = 360
Thus option A is correct
The answer is $182
300-200=100
100 x 0.36 = 36
146 + 36 = 182
Answer:
y+12=30
The cost is $18 per cup
Step-by-step explanation:
This is a word problem leading to linear equation
Let the prize of plates be x
Let the prize cups be y
We can now express the problem Mathematically as
x+2y= 60
24+2y= 60
We can arrange the equation as
2y+24= 60
Dividing through by 2
y+12=30
The equation to help determine the price of one cup is y+12=30
We can solve for y
y= 30-12
y= 18
A cup cost $18
"<span>-9m^-2*n^5*2m^-3*n^-6" simplified down:
The answer to "</span><span>-9m^-2*n^5*2m^-3*n^-6" (simplified) is: -648 -+-n^5+-
This is a verified answer. </span>