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3 years ago

Which is an acceptable Lewis structure for a diatomic nitrogen molecule?

1 answer:

4 0

Answer:
Acceptable Lewis structure of Diatomic Nitrogen Molecule is as follow,

:N≡N:

Explanation:
The given lewis structure is acceptable because each nitrogen atom has a complete octet and and the formal charge of each nitrogen atom is zero. So those lewis structures which has zero or least formal charges are said to be more stable and acceptable. The formal charge is calculated is,

Formal Charge = # of Valence e⁻s - [# of non-bonded e⁻ + 1/2 # of bonded e⁻]

For N,

Formal Charge = 5 - [ 2 + 6/2]

Formal Charge = 5 - [ 2 + 3 ]

Formal Charge = 5 - 5

Formal Charge = 0

Same result will come for the second N atom.

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2H2 + O2 → 2H2O

pantera1 [17]

Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles

moles of O2 is half
so 40.04 x 0.5
20.02moles

grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g

6 0

3 years ago

Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?

Arlecino [84]

5.58 X $10^{-25}$ Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273 K

Pressure at STP = 1 atm

volume = ?

R (gas constant) = 0.08201 L atm/mole K

to convert molecules to moles,

number of moles = $\frac{molecules}{Avagadro's number}$

number of moles = 2.49 x $10^{-26}$

Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V = $\frac{nRT}{P}$

putting the values in the rearranged equation:

V = $\frac{2.49 X10^{-26} X 0.08201 X 273}{1}$

V = 5.58 X $10^{-25}$ Litres.

5 0

3 years ago

CHEMISTRY!! 50 POINTS!

Anuta_ua [19.1K]

Answer:

The answer to this question is 33.8

6 0

3 years ago

Why is an atom regarded as electrically unstable

meriva

Answer: An atom can be considered unstable in one of two ways. If it picks up or loses an electron, it becomes electrically charged and highly reactive. Such electrically charged atoms are known as ions. Instability can also occur in the nucleus when the number of protons and neutrons is unbalanced.

Explanation:

5 0

3 years ago

10.0 g Cu, C Cu = 0.385 J/g°C 10.0 g Al, C Al = 0.903 J/g°C 10.0 g ethanol, Methanol = 2.42 J/g°C 10.0 g H2O, CH2O = 4.18 J/g°C

Mazyrski [523]

Answer:

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

Explanation:

$Q=mc\Delte T$

Q = Energy gained or lost by the substance

m = mass of the substance

c = specific heat of the substance

ΔT = change in temperature

1) 10.0 g of copper

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the copper = c = 0.385 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.385J/g^oC}=25.97^oC$

2) 10.0 g of aluminium

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the aluminium= c = 0.903 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.903 J/g^oC}=11.07^oC$

3) 10.0 g of ethanol

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the ethanol= c = 2.42 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 2.42 J/g^oC}=4.13 ^oC$

4) 10.0 g of water

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the water = c = 4.18J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 4.18 J/g^oC}=2.39 ^oC$

5) 10.0 g of lead

Q = 100.0 J (positive means that heat is gained)

m = 10.0 g

Specific heat of the lead= c = 0.128 J/g°C

$\Delta T=\frac{Q}{mc}$

$=\frac{100.0 J}{10 g\times 0.128 J/g^oC}=78.125^oC$

Lead shows the greatest temperature change upon absorbing 100.0 J of heat.

3 0

4 years ago