To solve for the probability proportion, we make use of
the z statistic. The procedure to do is to calculate for the z value and using
the standard probability tables, we can look up for the p value. The formula
for z score is:
z =(x – μ) / (σ / sqrt(n))
where,
x = sample score = 11
μ = sample mean= 10
σ = standard deviation = 2
n = sample size
Calculating for the z and p value when n = 5:
z =(11 – 10) / (2 / sqrt(5))
z = 1.12
Using the tables, p(5) = 0.8686
Calculating for the z and p value when n = 6:
z =(11 – 10) / (2 / sqrt(6))
z = 1.22
Using the tables, p(6) = 0.8888
If both days should be occuring, therefore the total
probability that each day is at most 11 min is:
p total = p(5) * p(6)
p total = 0.8686 * 0.8888
p total = 0.772
The answer is -2 because 8(-2)-3=-19
8(-2)= -16-3=-19
Answer:
P= Rs 60000
A= Rs 79860
T=1 & 1/2 year = 3/2 years
= 3/2 x 2 = 3 half years
R= ?
Applying the formula A= P (1+r/100)^T
79860 = 60000 (1+ r/100)^3
79860/60000 = (1+r/100)^3
1331/1000 = (1+r/100)^3
root(3)(1331/1000) = (1+r/100)
11/10 = 1+r/100
11/10 -1 = r/100
1/10 = r/100
r= 10 %
Step-by-step explanation:
Answer: D
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
t x 5 = 60
60/5 = 12
