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olga2289 [7]
3 years ago
12

I need help on all of them

Physics
1 answer:
oksano4ka [1.4K]3 years ago
6 0
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Which is the smallest unit of life?
emmasim [6.3K]

Answer:

the cell is the smallest unit

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2 years ago
What are the similarities and differences between an electric bell and a circuit breaker​
alexgriva [62]

Answer:

differences and similarities

Explanation:

An electric bell is a mechanical or electronic bell that functions by means of an electromagnet. When an electric current is applied, it produces a repetitive buzzing, clanging or ringing sound. whereas,

A circuit breaker is an automatically operated electrical switch designed to protect an electrical circuit from damage caused by excess current from an overload or short circuit. Its basic function is to interrupt current flow after a fault is detected.

5 0
4 years ago
Ryan places 0.150 kg of boiling water in a thermos bottle. How many kgs of ice at –12.0 °C must Ryan add to the thermos so that
Greeley [361]

Answer:

The  value  is   m_i =  0.0234 \  kg

Explanation:

Generally from the calorimetry principle we have that

      Heat \ loss\ by\ ice  =  heat\ gained\ by\  water\

So here heat gained water is mathematically represented as i.e

      Q_w  = m_w  *  c_w *  (T_w - T )

substituting  0.150 kg for m_w , 4200 J/kg.°C for  c_w , 100°C for   T_w and  75°C for  T

We have  

       Q_w  = 0.150  *  4200 *  (100 - 75 )

         Q_w  =15750 \  J

The Heat loss by the ice is mathematically represented as

      Q_i  = Q_1 + Q_2 +  Q_3

Here     Q_1 is the energy to move the ice to its melting point which is evaluated as  

        Q_1  =  m_i *  c_i * ( T_o -T_i)

Here  m_i is the mass of  ice

       c_i is the specific heat of ice with value  2.05 * 10^3   J/kg.°C

          T_o temperature of ice at melting point with value 0°C

           T_i is the temperature of ice with value  -12°C

Q_2 is the energy to move the ice from its  its melting point to liquid which is evaluated as  

     Q_2  = m_i  *  L

        Here  L  is the Latent heat of melting of ice with value    334 * 10^3   J/kg

Q_3 is the energy to move the ice from  liquid  to  the equilibrium temperature  which is evaluated as        

       Q_1  =  m_i *  c_w * ( T -T_o)

So  

     Q_i  = m_i [ c_i * ( T_o -T_i) + L  + c_w * ( T -T_o) ]

=>   Q_i  = m_i [ 2.05 * 10^3 * ( 0 -(-12)) + 334 * 10^3  +  4200 * ( 75 - 0) ]

From

 Heat \ loss\ by\ ice  =  heat\ gained\ by\  water\

We have that

  m_i *  673600  =15750

=>     m_i =  \frac{15750}{673600}

=>     m_i =  0.0234 \  kg

8 0
4 years ago
Which physical property refers to the temperature at which a substance in a solid-state transforms to a liquid state?
solmaris [256]

Answer:

C: Melting point

Explanation:

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3 years ago
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A brick is dropped from a height of 31.9 meters
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