Answer:
3.95979 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Here 
Initial velocity of the puck should be 3.95979 m/s
Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:
F = (k*Q1*Q2)/d^2
k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.
As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.
Answer:
constructive interference.
Explanation:
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m.
In this scenario, an experiment is conducted by Pierce in which waves collide in a way that the energy increases. Thus, this is an example of constructive interference i.e constructive interference has occurred.
An interference occurs when two pair of waves such as sound and light waves pass through each other i.e crossing each other's path while traveling through the same medium or space.
Answer:
0.17
Explanation:
Draw a free body diagram. There are five forces on the box:
Weight force mg pulling down
Normal force Fn pushing up
Applied force 52 N pulling to the left
Applied force 125 N pulling to the right
Friction force Fnμ pulling to the left
Sum of the forces in the y direction:
∑F = ma
Fn − mg = 0
Fn = mg
Fn = (45)(9.8)
Fn = 441
Sum of the forces in the x direction:
∑F = ma
125 − 52 − Fnμ = 0
Fnμ = 73
μ = 73 / Fn
μ = 73 / 441
μ = 0.17
