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AveGali [126]
3 years ago
15

What is 0.574 rounded to the nearest hundredth?

Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

B .57

Step-by-step explanation:

hundredths place is the second decimal place. And because the thousandths place is less than 5, you round down.

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Gaurav takes 15 rounds of a rectangular park whose length is twice its breadth. If the total distance covered by Gaurav is 900m
Dvinal [7]

Answer:

length = 20 breadth = 10

Step-by-step explanation:

divide 900 by 15

= 60

60 divided by 6 because the length is twice the breath

60 / 6 is 10

so ten is the breadth of one side and double that is 20 so the length is 20

Hope this helped!

4 0
3 years ago
8x+5 <br> 3x+8<br> Find the measurement of x!!
Soloha48 [4]

Answer:

Step-by-step explanation: look at the picture

8 0
3 years ago
estimate 0.00792398 to the nearest thousandth. Express your answer as a single-digit times a power of ten
Marianna [84]

Answer: \approx8*10^{-3}

Step-by-step explanation:

In order to round to the nearest thousandth, you must observe the digit to the right of the digit in the thousandth place and then:

  • If it is less than 5, you must round down.
  • If it is greater than or equal than 5, you must round up.

In this case, given the number:

0.00792398

You can notice that the digit to the right of the digit in the thousandth place is 9.

Since 9>5, you must round up. Then:

0.00792398\approx0.008

Finally, to express this as a single-digit times a power of ten, move the decimal point three places to the right. Then you get:

\approx8*10^{-3}

5 0
3 years ago
Please please please help
tia_tia [17]
It’s false!!! Hope this helped;)
3 0
3 years ago
Read 2 more answers
In triangle ΔABC, ∠C is a right angle and CD is the height to AB . Find the angles in ΔCBD and ΔCAD if: Chapter Reference a m∠A
Strike441 [17]

Answer:

Given A triangle ABC in which

 ∠C =90°,∠A=20° and CD ⊥ AB.

In Δ ABC

⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]

⇒20° + ∠B + 90°=180°

⇒∠B+110° =180°

∠B =180° -110°

∠B = 70°

In Δ B DC

∠BDC =90°,∠B =70°,∠BC D=?

∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]

90° + 70°+∠BC D =180°

∠BC D=180°- 160°

∠BC D = 20°

In Δ AC D

∠A=20°, ∠ADC=90°,∠AC D=?

∠A +  ∠ADC +∠AC D=180° [angle sum property of triangle]

20°+90°+∠AC D=180°

110° +∠AC D=180°

∠AC D=180°-110°

∠AC D=70°

So solution are, ∠AC D=70°,∠ BC D=20°,∠DB C=70°





5 0
4 years ago
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