Question

A force of 20 N acts on a smaller piston of a hydraulic press with an area of ​​10 dm2. How much force does the liquid act on a larger piston of 120 cm2?​

Answer 1

Answer:

166.6 N

Explanation:

Given that,

Force, F₁ = 20 N

Area, A₁ = 10 dm² = 1000 cm²

We need to find the new force if the area of the larger piston is 120 cm². According to Pascal's law,

$F_1A_1=F_2A_2\\\\F_2=\dfrac{F_1A_1}{A_2}\\\\F_2=\dfrac{20\times 1000}{120}\\\\F_2=166.7\ N$

So, the force on the larger piston is equal to 166.7 N.