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Ugo [173]
3 years ago
10

Which of these forms of energy is NOT regularly given off by the sun?

Physics
1 answer:
IceJOKER [234]3 years ago
4 0
D: Ultraviolet Rays is the answer hope that helps
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Oil at 150 C flows slowly through a long, thin-walled pipe of 30-mm inner diameter. The pipe is suspended in a room for which th
chubhunter [2.5K]

Answer:

<em>1.01 W/m</em>

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above,<em> we assumed that the pipe wall and the oil are in thermal equilibrium</em>.

area of the pipe per unit length A = \pi r ^{2} = 7.069*10^{-4} m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = <em>1.01 W/m</em>

4 0
3 years ago
A projectile is shot from the edge of a cliff h = 185 m above ground level with an initial speed of v0 = 145 m/s at an angle of
OleMash [197]
I'm going too hell for putting answers that are not really good enough for you but I need my answers and I need help with my answers
6 0
4 years ago
The number of wavelengths that pass a given point/second is called
myrzilka [38]

Answer:

I believe the answer is frequency

Hope this helps!! (let me know if it is right)

Explanation:

6 0
3 years ago
An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
Lesechka [4]

Answer:

+1/3

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative: f=-f

and we also know that the object is placed a distance of twice the focal length, so p=2f

So we can find q from the equation above

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

And the magnification of the image is given by

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

5 0
4 years ago
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The primary source of the Sun's energy is:_________
kolezko [41]
The dusting of hydrogen into helium. HOPE THIS HELPEDD
7 0
4 years ago
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