What is the least positive integer such that it is a multiple of 16 and the product of its digits is a multiple of 12?
1 answer:
Answer:
24
Step-by-step explanation:
Multiples of 16 are
Find product of each of the multiple of 16 until a number is obtained, the product of whose digits is a multiple of 12.
Here, 24 is a multiple of 12.
So,
24 is the least positive integer such that it is a multiple of 16 and the product of its digits is a multiple of 12.
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Answer:
7.789×10^-2 = 0.07789 cm
Step-by-step explanation:
Your calculator can find the difference of the two given diameters and express it in any format you like.
The attached image of a calculator display shows the difference of the cell diameters is 0.07789 = 7.789×10^-2 cm.
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The difference of two numbers with different exponents is found by first adjusting the exponents so they are the same. Here, we choose to adjust both numbers so they have the highest exponent value.
8.83×10^-2 - 6.01×10^-3
= 8.39×10^-2 - 0.601×10^-2 = (8.39 -0.601)×10^-2 = 7.789×10^-2
Alternatively, you can convert both numbers to standard form and do the subtraction that way.
8.83×10^-2 - 6.01×10^-3
= 0.0883 -0.00601 = 0.07789
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<em>Additional comment</em>
The second attachment shows the relationship between place values and their multiplier in scientific notation.
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The choice of exponent when computing the sum or difference of numbers in scientific notation is usefully informed by an estimate of the value of the sum or difference. A proper choice can avoid the need to adjust the exponent of the result of the operation. Here, we see the subtraction will change the larger value by less than 10%, so the exponent of the result in scientific notation will be that of the larger value (-2).
