Question

What is the least positive integer such that it is a multiple of 16 and the product of its digits is a multiple of 12?

Answer 1

Answer:

24

Step-by-step explanation:

Multiples of 16 are $16,32,48,64,80,...$

Find product of each of the multiple of 16 until a number is obtained, the product of whose digits is a multiple of 12.

$16=1(6)=6\\32=3(2)=6\\48=4(8)=32\\64=6(4)=24$

Here, 24 is a multiple of 12.

So,

24 is the least positive integer such that it is a multiple of 16 and the product of its digits is a multiple of 12.