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4 years ago

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?

Mathematics

2 answers:

Lorico [155]4 years ago

7 0

Answer:

Step-by-step explanation:

bonufazy [111]4 years ago

4 0

Remark

Start with the ones that are wrong because they are in the wrong order.

To find F(n + 1) in a recursive formula, it must be by itself on the left. That makes B wrong.

Find out the difference in the sequence

You are subtracting 6 from the current term to get to the next term. There is no multiplication anywhere. That makes D wrong.

Now to distinguish A and C, you have to decide between addition and subtraction

You are subtracting 6 from the current term to get to the next one.

C <<<<< Answer

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Solve the system of linear equations below.

matrenka [14]

Answer:

A. x=4 y=11

Step-by-step explanation:

y=x+7

y=-2(y-7)+19

y=-2y+14+19

y=-2y+33

y+2y=33

y(1+2)=33

y=33/3

y=11

x=4

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3 years ago

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mr Goodwill [35]

Answer:

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Step-by-step explanation:

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3 years ago

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Factor the expression 10x^5+x^2-15

FinnZ [79.3K]

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4 years ago

Find, then state if it’s a function

valentina_108 [34]

Answer:

The answer is y = ± $\sqrt[4]{\frac{x}{4}}$ , $f^{-1}(x)$ is a function ⇒ 1st answer

Step-by-step explanation:

Let us revise the steps of find the inverse of a function

Replace f(x) with y
Replace every x by y and replace y by x
Solve the equation in Step 2 for y
Replace y by $f^{-1}(x)$

∵ $f(x)=4x^{4}$

- Replace f(x) by y

∴ $y=4x^{4}$

- Replace y by x and x by y

∴ $x=4y^{4}$

- Divide each side by 4

∴ $\frac{x}{4}=y^{4}$

- Take $\sqrt[4]{}$ for both sides

∴ ± $\sqrt[4]{\frac{x}{4}}=y$

- Switch the two sides

∴ y = ± $\sqrt[4]{\frac{x}{4}}$

∵ There is no fourth root for negative number

∴ x ≥ 0

When you test the graph of $f^{-1}(x)$ by a vertical line, it will cut it just at one in every position, so it is a function. Look to the attached graph for more understand

∴ $f^{-1}(x)$ is a function

The answer is y = ± $\sqrt[4]{\frac{x}{4}}$ , $f^{-1}(x)$ is a function

8 0

3 years ago