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Sidana [21]
4 years ago
10

Which simplified fraction is equal to 0.53? 24/45 8/15 48/90 5/9

Mathematics
2 answers:
Bad White [126]4 years ago
5 0

Answer:

The simplified fraction that is equal to 0.53 is 24/45, 8/15, and 48/90.

All of these are correct depending on which one you want.

I hope this was helpful. :D

ziro4ka [17]4 years ago
3 0

Answer:

All with the exception of 5/9.

Step-by-step explanation:

You can figure out which fraction is equal to.53 by dividing the numerator by the denominator to get a decimal.

Edit: Sorry I forgot the division symbol.

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The <em><u>correct answer</u></em> is:

C. Both (house, complete mailing address) and (complete mailing address, house) are functions.

Explanation:

A function is a relation in which each element of the domain (x-values) is mapped to one element of the range (y-values).

In the set (house, complete mailing address), the values of "house" would be the domain and the values of "complete mailing address" would be the range.  In order to be a function, each value of "house" would be mapped to only one value of "complete mailing address."  This is true; each house will have only one complete mailing address.  This means it is a function.

In the set (complete mailing address, house), the values of "complete mailing address" would be the domain and the values of "house" would be the range.  In order to be a function, each value of "complete mailing address" would be mapped to only one value of "house."  This is true; each complete mailing address would go with only one house.  This means it is a function.

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Which is Not equal to thr absolute value of -5?
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In how many different ways can 2/15 be represented as 1/a+1/b, if a and b are positive integers with a greater than or equal to
Dmitrij [34]

Answer:

There are three possible combinations of positive integers such that a > b:

(1)  a = 15  and  b = 15

(2)  a = 20  and b = 12

(3)  a = 45  and  b = 9

Step-by-step explanation:

Notice that the possible factors (different from "1") of the denominator "15" are: 3, 5, and 15.

The answer for the case a = 15 and b = 15 is obvious since :

\frac{1}{15} + \frac{1}{15} = \frac{2}{15}

Then the possibility of a multiple of 5 for one of the denominators (let's say 5*n) and a multiple of 3 (let's say 3*m)for the other one  gives the general equation:

\frac{1}{5n} +\frac{1}{3m} =\frac{2}{15}

which should verify the following as we try to solve for one of the unknowns multiplicative factors  which by the way have to be positive for the requirement given in the problem:

\frac{5n+3m}{15mn}  =\frac{2}{15}\\\frac{5n+3m}{mn}  =\frac{2}{1}\\5n+3m=2mn\\\frac{5n+3m}{mn} =2\\\frac{5}{m} +\frac{3}{n} =2\\\frac{5}{m}=2-\frac{3}{n}

This last equation is very simple to analyze using integer values for "n" which would render a positive value on the right hand side, and then check from that set the ones that give an integer for the value "m".

Those found were:

For n=3, and m=5, a=15, and b=15 (the obvious solution discussed above)

\frac{1}{15} +\frac{1}{15}=\frac{2}{15}

For n = 4 and m = 4, a = 20, and b = 12

\frac{1}{20} +\frac{1}{12}=\frac{32}{240}=\frac{2}{15}

and for n=9 and m=3, a=45 and b = 9

\frac{1}{45} +\frac{1}{9}=\frac{54}{405}=\frac{2}{15}

4 0
4 years ago
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