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3 years ago

Which simplified fraction is equal to 0.53? 24/45 8/15 48/90 5/9

Mathematics

2 answers:

Bad White [126]3 years ago

5 0

Answer:

The simplified fraction that is equal to 0.53 is 24/45, 8/15, and 48/90.

All of these are correct depending on which one you want.

I hope this was helpful. :D

ziro4ka [17]3 years ago

3 0

Answer:

All with the exception of 5/9.

Step-by-step explanation:

You can figure out which fraction is equal to.53 by dividing the numerator by the denominator to get a decimal.

Edit: Sorry I forgot the division symbol.

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A group of friends wants to go to the amusement park. They have no more than $125 to spend on parking and admission. Parking is

lisov135 [29]

Answer:

100

Step-by-step explanation:

8 0

3 years ago

In Illinois, 10 % of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been ar

docker41 [41]

Answer:

a) P(X=5) = 0.065

b) P(X≥1) = 0.928

c) The mean number of repeat offenders is 3.

d) The standard deviation of the number of repeat offenders is 2.

Step-by-step explanation:

n = 25

p = 10% = 0.10

q = 1-p

= 1-0.1

q=0.9

a) Find P(X =5)

Using the binomial distribution formula:

P(X = x) = ⁿCˣ pˣ qⁿ⁻ˣ

where p = probability of success

q = probability of failure

n = total number of trials

x = no. of successful trials

P(X=5) = ²⁵C₅ (0.1)⁵ (0.9)²⁵⁻⁵

= 0.0645 ≅ 0.065

P(X=5) = 0.065

b) We need to find the probability that at least one person is a repeat offender which means at most there can be 25 repeat offenders hence, we need to compute the probability for all values ranging from 1 to 25. The easy way to solve this problem is to find out the probability of less than one repeat offender and then subtract the value from the total probability (i.e. 1).

P(X≥1) = 1 - P(X<1)

= 1 - P(X =0)

= 1 - ²⁵C₀ (0.1)⁰ (0.9)²⁵⁻⁰

= 1 - 0.072

P(X≥1) = 0.928

c) The mean of the binomial distribution is:

μ = np

So, the mean number of repeat offenders can be computed as:

μ = (25)(0.10)

μ = 2.5 ≅ 3

The mean number of repeat offenders is 3.

d) The standard deviation of the binomial distribution is:

σ = √npq

So, the standard deviation of the number of repeat offenders can be computed as:

σ = √(25)(0.1)(0.9)

= √2.25

σ = 1.5 ≅ 2

The standard deviation of the number of repeat offenders is 2.

7 0

3 years ago

The combined height of one for tree and one pine tree is 21 meters. The height of 4 for trees stacked on top of each other is 24

slamgirl [31]

Answer:

The height of the fir tree is 9 meters tall and the pine tree is 12 meters.

Step-by-step explanation:

Given:

Note :→ there is a mistake it is fir tree not for tree.

The combined height of one fir tree and one pine tree is 21 meters.

The height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Now, to find how tall are the types of trees.

Let the height of one fir tree be $x$ .

And the height of one pine tree be $y$ .

So, the combined height of one fir tree and one pine tree:

$x+y=21.$

$y=21-x.$ .........( 1 )

Now, as given the height of 4 for trees stacked on top of each other is 24 meters taller than one pine tree:

$4x=y+24.$

Putting the value of equation (1) in the place of $y$ :

$4x=21-x+24$

Adding both the sides $x$ we get:

$5x=21+24.$

$5x=45.$

Dividing both the sides by 5 we get:

$x=9\ meters.$

So, the height of one fir tree = 9 meters.

Now, putting the value of $x$ in equation (1) we get:

$y=21-9$

$y=12\ meters.$

Thus, the height of one pine tree = 12 meters.

Therefore, the fir tree is 9 meters tall and the pine tree is 12 meters tall.

6 0

3 years ago

Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t

NeTakaya

Answer:

$\mu = 11$

$\sigma = 2.08$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when $Z = -1.44, X = 8$ . So

$Z = \frac{X - \mu}{\sigma}$

$-1.44 = \frac{8 - \mu}{\sigma}$

$8 - \mu = -1.44\sigma$

$\mu = 8 + 1.44\sigma$

Also, when X = 14, Z has a pvalue of 0.925, so when $X = 8, Z = 1.44$

$Z = \frac{X - \mu}{\sigma}$

$1.44 = \frac{14 - \mu}{\sigma}$

$14 - \mu = 1.44\sigma$

$1.44\sigma = 14 - \mu$

Replacing in the first equation

$\mu = 8 + 1.44\sigma$

$\mu = 8 + 14 - \mu$

$2\mu = 22$

$\mu = \frac{22}{2}$

$\mu = 11$

Standard deviation:

$1.44\sigma = 14 - \mu$

$1.44\sigma = 14 - 11$

$\sigma = \frac{3}{1.44}$

$\sigma = 2.08$

7 0

3 years ago

7b+11>9b-13 need to find b>?

STALIN [3.7K]

$7b+11 > 9b-13\ \ \ \ /-11\\\\7b+11-11 > 9b-13-11\\\\7b > 9b-24\ \ \ \ /-9b\\\\7b-9b > 9b-9b-24\\\\-2b > -24\ \ \ \ /:(-2) < 0\ then\ " > "\ change\ to\ "\ < "\\\\b < 12\\\\b\in(-\infty;\ 12)$

8 0

3 years ago