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3 years ago

What is the product of 2,930 and 4

Mathematics

2 answers:

vladimir2022 [97]3 years ago

7 0

2930 times 4 =11,720 Hope that helped Have a good day :)

Bess [88]3 years ago

7 0

The answer to the sum 2930*4=
2930
* 4
11720

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2 years ago

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3 years ago

Give the parallel cross-section for the following: Cylinder, cone, sphere, and pyramid.

Maurinko [17]

The parallel cross-sections of a cylinder, cone, sphere, and pyramid are a circle, a circle, a circle, and a square.

We are given some solids. Solid geometry, or stereometry, is the traditional name for the geometry of three-dimensional Euclidean spaces in mathematics. Stereometry is concerned with measuring the volumes of various solid figures. The given solids are a cylinder, cone, sphere, and pyramid. We need to find the parallel cross-sections of the given solids. Parallel cross sections are cross sections of a solid that are parallel to each other. A cross section is a straight slice of an object. The parallel cross-sections of a cylinder, cone, sphere, and pyramid are a circle, a circle, a circle, and a square.

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11 months ago

A cake recipe calls for 1 cup of oil. Jean needs to make 12 cakes for her school bake sale. How many quarts of oil will Jean nee

kipiarov [429]

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7 0

3 years ago

Read 2 more answers

Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

$\frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)$

$\frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)$

Simplify the equation.

$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)$
$\frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )$

Therefore, this is the 2nd derivative of the function f(x).

We can say that: $f''(x)=36x^2+4$

6 0

2 years ago

Read 2 more answers