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rosijanka [135]
3 years ago
10

Find the erea of the trapezoid.

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

9514 1404 393

Answer:

  32 yd²

Step-by-step explanation:

Use the area formula with the given dimensions.

  A = 1/2(b1 +b2)h . . . . . base lengths b1, b2; height h

  A = 1/2(2 +6)8 = 1/2(8)(8) = 32 . . . . square yards

The area of the trapezoid is 32 square yards.

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What is the research hypothesis when using anova procedures?
Pachacha [2.7K]

When using ANOVA procedures, the research hypothesis is: there is no significance difference within the mean values of the groups.

<h3>What is a Research Hypothesis in ANOVA Procedure?</h3>

ANOVA procedure compares the mean values of different groups that are administered with treatments. The research hypothesis, such as the null hypothesis would be stated as: no significance difference in the mean values within the groups.

Thus, we can conclude that the research hypothesis when using the ANOVA procedures can be stated as a null hypothesis, which states that: there is no significance difference within the mean values of the groups.

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2 years ago
PLEASE HELP WILL MARK BRAINLIEST!
pav-90 [236]

Answer:

1, 5, 17, 53, 161

Step-by-step explanation:

Given:

  • a_1=1
  • a_n=3a_{n-1}+2

First five terms of the sequence:

a_1=1

a_2=3a_1+2=3(1)+2=5

a_3=3a_2+2=3(5)+2=17

a_4=3a_3+2=3(17)+2=53

a_5=3a_4+2=3(53)+2=161

7 0
2 years ago
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What does it mean to say that a data point has a residual of 1?
aleksandrvk [35]
This your answer hope i helped. :)

<span> The point lies one unit above the regression line. </span>
4 0
3 years ago
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Find the number of permutations of the first 9 letters of the alphabet, taking 4 letters at a time.
Vinil7 [7]

Solution-

First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I

Total number of ways of selection of 4 letters from 9 alphabets = 9C4

=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126

The number of ways of arranging these 4 numbers = 4! = 24

∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024

∴ option number 2 is correct.

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4 years ago
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If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then m
Korvikt [17]

Answer:

The final integration in the given limits will be 89.876

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3 years ago
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