Answer:
A. OU
Explanation:
An organization unit (OU) is used to group objects that are related, having similar administrative and security requirements within a domain. It provides a way of classifying objects in a directory, such as differentiating between objects with the same name or managing and creating objects. An OU can be nested into another OU, thus it can be used to create a hierarchy within an organization.
Answer:
I1 to K2: Use a formula to link the cells. Create a formula in column L that calculates the averages for each matching category in K2:
<h3>hope it's help you </h3><h3>plz mark as brain list </h3>
An anaglyph is a graphic image composed of two images, one that is tinted red and the other that is tinted blue. When viewed together these images produce a stereoscopic effect.
Further Explanation:
To explain what an Anaglyph is and the concept it uses to work, I will use a simple demonstration. Place your finger higher up at a shorter distance from your face and close your left eye. You will notice your finger move slightly a bit to the left. The same happens when you close your right eye too.
Basically, Anaglyphs work by laying one images over the other from two angles. One image has a red tint and the other a blue tint. To view an Anaglyph image, you need glasses with the corresponding colors of the image. Note that if the image for the right eye is blue, it can only be filtered out by the red lense and not the blue lense and vice versa.
Learn more about anaglyph by clicking the image below
brainly.com/question/11507732
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Answer:
C++ Code:
void sort3(double &a, double &b, double &c)
{
if(a > b)
swapdoubles(a,b);
if (b > c)
swapdoubles(b,c);
if (a > b)
swapdoubles(a,b);
}
Explanation:
To change the values of a,b,c within the function, we pass the values by reference. Let us assume that number a = 3.14, b = 2.71, c = 3.04. Since a > b, values of a and b will be swapped.Now a = 2.71 and b = 3.14. Similariy, since b > c, they will be swapped. This way, we move the largest number to its correct position in the first two steps. If there are only three numbers, and the largest number is in its correct position, then for the two remaining numbers, we will only need atmost one swap to exchange their positions. hence, we perform a comparison of a > b once again to see if the b is smaller than a. if its not, then all a,b,c are in sorted order.
