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3 years ago

Daniel made a bench that has a seat with an area of 16 square feet.

Mathematics

1 answer:

balandron [24]3 years ago

7 0

Answer:

A: 2 feet by 6 feet

Step-by-step explanation:

Hopefully this helps!

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What is the answer for this -12n - (-13n)=

Ksenya-84 [330]

Answer:

Step-by-step explanation:

-12n - (-13n) = -12n +13n = 1n

8 0

2 years ago

Which of the x-values satisfy the following inequality?

Vinil7 [7]

Answer:

c. x=3

Step-by-step explanation:

Given:

7x < 21

Divide both sides by 7

7x / 7 < 21 / 7

x < 21/7

x < 3

x = 3

Check:

7x < 21

7(3) < 21

21 = 21

5 0

2 years ago

NEED HELP FAST!!!

baherus [9]

We know the y intercept is 16 because y=16 when x=0.

Find slope by calculating change in y over change in x.
(12-16)/(2-0)
-4/2
-2

Plug both values into slope intercept form. y=mx+b where m is slope and b is the y intercept.

Final answer: y=-2x+16

4 0

3 years ago

What is the exact volume of the cylinder?

AURORKA [14]

Answer:

Step-by-step explanation:

8 cm and the height is 15 cm.

8 0

2 years ago

A large tank is filled to capacity with 600 gallons of pure water. brine containing 4 pounds of salt per gallon is pumped into t

nignag [31]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which the amount of salt in the tank changes is given by

$\dfrac{\mathrm dA(t)}{\mathrm dt}=\dfrac{4\text{ lbs}}{1\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}-\dfrac{A(t)\text{ lbs}}{600\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}$
$\dfrac{\mathrm dA}{\mathrm dt}=24\dfrac{\text{lb}}{\text{min}}-\dfrac{A(t)}{100}\dfrac{\text{lb}}{\text{min}}$

Let's drop the units for now. We have

$\dfrac{\mathrm dA(t)}{\mathrm dt}+\dfrac{A(t)}{100}=24$
$e^{t/100}\dfrac{\mathrm dA(t)}{\mathrm dt}+e^{t/100}\dfrac{A(t)}{100}=24e^{t/100}$
$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/100}A(t)\right]=24e^{t/100}$
$e^{t/100}A(t)=\displaystyle24\int e^{t/100}\,\mathrm dt$
$e^{t/100}A(t)=2400e^{t/100}+C$
$A(t)=2400+Ce^{-t/100}$

We're given that the water is pure at the start, so $A(0)=0$ , giving

$A(0)=0=2400+Ce^{-0/100}\implies C=-2400$

So the amount of salt in the tank (in lbs) at time $t$ is

$A(t)=2400\left(1-e^{-t/100}\right)$

4 0

2 years ago