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svp [43]
3 years ago
5

Show work please and correct

Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

-  \frac{1}{2}

its down 1 over 2 each time

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Marysya12 [62]

The answer would be 241.2

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3 years ago
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What is the exact area of a circle with a diameter of 20 cm?
Kisachek [45]
Hi there! The answer is 100πcm^2

The radius of a circle can be found by dividing the diameter by 2. In other words : the radius is half of the diameter.
Therefore, the radius of a circle with a diameter of 20 cm is 10 cm.

The exact area of a circle can be found using the following formula:
a = \pi \times \: {r}^{2} \\ with \\ a = area \\ r = radius

In order to find our answer, we need to plug in the data from the question.
a = \pi \: \times {10}^{2} = 100\pi

Hence, the answer is 100πcm^2.
5 0
3 years ago
PLS HELP! WILL GIVE BRAINLIEST
Leviafan [203]

Answer:

  • The center (2, 2.5), radius \sqrt{37} / 2

Step-by-step explanation:

<u>The standard form of the equation of a circle is: </u>

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<u>Rewrite the given equation in the standard form:</u>

  • 2x^2 + 2y^2 - 8x + 10y + 2 = 0
  • x^2 - 4x + y^2 + 5y = -1
  • x^2 - 4x + 2^2 + y^2 + 5y + (5/2)^2 = -1 + 4 + 25/4
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<u>The center is:</u>

  • (2, 2.5)

<u>And radius is:</u>

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4 0
3 years ago
Ida is cutting a 11/12 foot wooden board into 3/16 foot sections to do some detail work on a model she is building. How many who
zlopas [31]
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3 years ago
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Please help Factor completely. Show your work (as much work as possible, including a ​list of factors if
Elena-2011 [213]

Answer:

Step-by-step explanation:

4) x² - 14x + 48

We would find two numbers such that their sum or difference is -14x and their product is 48x².

The two numbers are - 6x and - 8x. Therefore,

x² - 6x - 8x + 48

x(x - 6) - 8(x - 6)

(x - 8)(x - 6)

5) 2x² + 21x - 11

We would find two numbers such that their sum or difference is 21x and their product is - 22x².

The two numbers are 22x and - x. Therefore,

2x² + 22x - x - 11

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6) 5a² - 125

5 is a common factor. So we would factorize 5. It becomes

5(a² - 25)

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3 years ago
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