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dedylja [7]
3 years ago
15

1. Which is greater 25% of 90 or 28% of 82.

Mathematics
2 answers:
rosijanka [135]3 years ago
4 0

Answer:

28% of 82

Step-by-step explanation:

25% of 90 is 22.5

28% of 82 is 22.96

vazorg [7]3 years ago
3 0

Answer:

28% of 82 is greater than 25% of 90.

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Which of the following are characteristics of the graph of the reciprocal parent function? check all that apply
e-lub [12.9K]
<h3>3 answers: Choice A, Choice C, Choice D</h3>

Basically, everything but choice B

===========================================

Explanation:

Lets go through the answer choices to see which are true or false.

For each, we'll be considering the graph of y = 1/x as shown below.

  • A. True. We have two branches that are completely separate and never meet up, and those two branches are in quadrants Q1 and Q3. Both curves are always decreasing (going downhill as you move from left to right). This is because if x is positive, then so is y = 1/x. If x is negative, then so is y = 1/x. Any point (x,y) is either composed of two positive coordinates or two negative coordinates.
  • B. False. A parabola is one single curve and we have two separate curves here.
  • C. True. A hyperbola is composed of two curves as the graph of y = 1/x shows.
  • D. True. The graph shows y = 1/x does not go through the origin. This is because we cannot have x = 0 in y = 1/x, or otherwise we have a division by zero error. A similar situation happens with y = 0 as well.

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3 years ago
The sports shop has 57 part-time employees and 19 full-time employees. What percentage of the employees at the sports shop work
Anna [14]
The answer is 75%. To find this answer, you add 57 and 19 to get the total workers which is 76. Then, you find the percentage of 57 out of 76. 57 divided by 76 is .75, bu to get the percent, you have to move the decimal two places to the right.
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One fourth the difference of four sixths and three twelfth
Lyrx [107]
1/4 (4/6 - 3/12) = 1/4 (5/12) = 5/48
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What is the GCF of 45 and 60
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15 is the GcF for 45 and 60
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The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot
Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

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