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aleksley [76]
3 years ago
14

(please help me with these)

Mathematics
1 answer:
Finger [1]3 years ago
3 0

9514 1404 393

Answer:

  1. V = 125 m³
  2. l = 7.5 cm

Step-by-step explanation:

You have not told us the sort of figure you're supposed to draw. If these are cuboids, then their drawings are substantially similar to the one shown in the attachment. Your figures may need to show the units on each of the dimensions.

1. A cube with edge lengths of 5 m has a volume of ...

  V = s³

  V = (5 m)³ = 125 m³

__

2. A cuboid with the given volume and other dimensions has a length of ...

  V = lwh

  675 cm³ = l(9 cm)(10 cm)

  675 cm³/(90 cm²) = l = 7.5 cm . . . . . . . . divide by the coefficient of l

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PLEASE HELP ME <br>...This is my homework and I don't understand how to do it.​
musickatia [10]

The probability that a point chosen at random lies in the shaded region is 0.28

<h3>Calculating the area of a shaded region and probability</h3>

From the question, we are to find the probability that a point chosen at random lies in the shaded region.

The shaded region is a triangle.

The probability that a point chosen at random lies in the shaded region = Area of the triangle / Area of the circle

First, we will calculate the unknown side of the triangle

Let the unknown side be x.

Then, from the <em>Pythagorean theorem</em>, we can write that

12² = 6² + x²

144 = 36 + x²

x² = 144 - 36

x² = 108

x = √108

x = 6√3

From formula,

Area of a triangle = 1/2 × base × height

Area of the triangle = 1/2 × 6 × 6√3

Area of the triangle = 18√3 square units

Now, we will determine the area of the circle

Area of a circle = πr²

Where r is the radius

From the given information,

Diameter of the circle = 12

But,

Radius = Diameter / 2

Therefore,

r = 12/2

r = 6

Thus,

Area of the circle = 3.14 × 6²

Area of the circle = 113.04 square units

Now,

The probability that a point chosen at random lies in the shaded region = 18√3 / 113.04

The probability that a point chosen at random lies in the shaded region = 0.2758

The probability that a point chosen at random lies in the shaded region ≈ 0.28

Hence, the probability is 0.28

Learn more on Calculating area of a shaded region here: brainly.com/question/23629261

#SPJ1

4 0
2 years ago
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substitute
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