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4 years ago

So if I have 4 over 5 what is the precent?

Mathematics

2 answers:

baherus [9]4 years ago

8 0

Answer:

Step-by-step explanation:

4 over 5 = 4/5

First, multiply 20 to both numerator and denominator:

(4/5)(20/20) = 80/100

Next, change the fraction into a decimal. move the decimal sign to the left two place values (and drop the denominator)

80/100 = 0.80

Next, to change the decimal to a percentage, move the decimal point to the right two place value and add the % sign.

0.80 = 80%

80% is your answer

levacccp [35]4 years ago

3 0

Answer:

The answer is 80%

Step-by-step explanation:

I tried to explain but I do not know how to word it out sorry:(

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0.003 convert to fraction

zlopas [31]

Answer: Its 3/1000

Step-by-step explanation:

Put 0.003 over 1 0.003/1 x 1000/1000 = 3/1000

5 0

4 years ago

Read 2 more answers

Urgently need help!!! I will mark the best answer as BRAINLIEST!!!!!

Lady bird [3.3K]

C. 16.4

Step-by-step explanation:

The formula to apply here is;

A=P(1+r/n) ^nt where

A=final amount

P=starting amount

r=rate of interest annually

n=number of compounding per year

t=time in years

Given ; P=$500, A=$750 , r=2.5%=0.025 , t=?,n=1

Substitute values;

A=P(1+r/n)^nt

$750=$500(1+0.025)^t

750=500(1.025)^t

750/500=(1.025)^t

1.5=(1.025)^t

log 1.5 =t log (1.025)

log 1.5/log 1.025 = t

16.4 =t

Learn More

Compound interest formula :brainly.com/question/12148233

Keywords : bank account, interest per year, value of account, years

#LearnwithBrainly

3 0

4 years ago

Solve each equation by completing the square. If necessary, round to the nearest hundredth.

Ksenya-84 [330]

$1.)\\ \\ b^2+10b=75\\ \\ b^2+10b-75=0\\ \\\Delta = b^{2}-4ac = 10^{2}-4*1*(75)=100+300=400 \\ \\\sqrt{\Delta }=\sqrt{400}=20$

$b_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-10-20}{2}=\frac{-30}{2}=-15\\ \\b_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-10+20}{2}=\frac{10}{2}=5$

$2.)\\ \\ n^2-20n=-75\\ \\ n^2-20n+75=0\\ \\\Delta = b^{2}-4ac = (-20)^{2}-4*1*75=400-300=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$n_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{20-10}{2}=\frac{10}{2}=5\\ \\n_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{20+10}{2}=\frac{30}{2}=15$

$3.)\\ \\t^2+8t-9=0\\ \\\Delta = b^{2}-4ac = 8^{2}-4*1* (-9)=64+36=100 \\ \\\sqrt{\Delta }=\sqrt{100}=10$

$t_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-8-10}{2}=\frac{-18}{2}=-9\\ \\t_{2}=\frac{-b+\sqrt{\Delta }}{2a} \frac{-8+10}{2}=\frac{2}{2}=1$

$4.)\\ \\m^2-2m-8=0\\ \\\Delta = b^{2}-4ac = (-2)^{2}-4*1* (-8)=4+32=36\\ \\\sqrt{\Delta }=\sqrt{36}=6$

$m_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{2-6}{2}=\frac{-4}{2}=-2\\ \\m_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{2+6}{2}=\frac{8}{2}=4$

$5.)\\ \\ v^2+4v-2=0\\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* (-2)=16+8=24\\ \\\sqrt{\Delta }=\sqrt{24}= \sqrt{4*6}=2\sqrt{6}$

$v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-2\sqrt{6}}{2}=\frac{2(-2-\sqrt{6}}{2}= -2-\sqrt{6}\approx -2-2,45\approx -4,45\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a}= \frac{-4+2\sqrt{6}}{2}=\frac{2(\sqrt{6}-2}{2}= \sqrt{6}-2 \approx 2,45-2\approx 0,45$

3 0

3 years ago

Simplify completely 3x + 18 / 18

disa [49]

Answer:

3(x + 6)/18

= x + 6 /6

Step-by-step explanation:

hope this helps you

4 0

3 years ago

If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=−16t2+123t. Find