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3 years ago

Help please ?!?!?!!???????!???!???!!????!!??!??!?!?!!??!?!!????

Mathematics

1 answer:

wariber [46]3 years ago

8 0

No association because it’s scattered

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Phone numbers in Italy are in the format AB-CDDD-XXXX and have the following conditions · A can be any number 3-9 · B can be any

amm1812

Answer:

Hey there!

A: 7

B: 6

C: 5

D: 7

X: 10

7x6x5x7x7x7x10x10x10=720,300,000

Let me know if this helps :)

8 0

3 years ago

Racehorse weighs 470 kilograms. How much does it weigh in grams

tigry1 [53]

Answer: 470000 grams

Step-by-step explanation:

1 kilogram =1000 grams

470×1000=470000

7 0

4 years ago

Read 2 more answers

Let f(x) = 3x^2 – 8x + 5 and let g(x) = 2x – 8. Find

fenix001 [56]

Answer:

B. 3x² – 10x + 13

Step-by-step explanation:

given:

f(x) = 3x² – 8x + 5

g(x) = 2x – 8

f(x) - g(x)

= (3x² – 8x + 5) - (2x – 8)

= 3x² – 8x + 5 - 2x + 8

= 3x² – 10x + 13

3 0

3 years ago

Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20

Vsevolod [243]

Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of $n$ are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

$Ax^{2} +Bx+C$

and the roots are: $\alpha$ and $\beta$

Then sum of roots, $\alpha+\beta = -\frac{B}{A}$

Product of roots, $\alpha \beta = \frac{C}{A}$

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots, $\alpha+\beta = -\frac{-m}{1} = m$

Product of roots, $\alpha \beta = \frac{n}{1} = n$

We are given that $m$

$\alpha$ and $\beta$ are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of $n (= \alpha \times \beta)$ are:

$1.\ 2, 2\Rightarrow n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow n = 6\\3.\ 2, 5 \Rightarrow n = 10\\4.\ 2, 7\Rightarrow n = 14\\5.\ 2, 11 \Rightarrow n = 22\\6.\ 2, 13 \Rightarrow n = 26\\7.\ 2, 17 \Rightarrow n = 34\\8.\ 3, 3\Rightarrow n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow n = 15\\10.\ 3, 7 \Rightarrow n = 21\\$

$11.\ 3, 11\Rightarrow n = 33\\12.\ 3, 13 \Rightarrow n = 39\\13.\ 5, 5 \Rightarrow n = 25\\14.\ 5, 7 \Rightarrow n = 35\\15.\ 5, 11 \Rightarrow n = 55\\16.\ 5, 13 \Rightarrow n = 65\\17.\ 7, 7 \Rightarrow n = 49\\18.\ 7, 11 \Rightarrow n = 77$

So,as shown above <em>18 values for n are possible.</em>

3 0

3 years ago

Help! Will give brainliest!

lawyer [7]

Answer:

6 or 5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers