<span>A full outer shell has 8 valence electrons, and since each nitrogen has only five, they both need three more to get to a full outer shell. However, since they're the same atom, and they need the same amount of electrons, they're going to form a covalent bond, where they both SHARE three (if one gave three to the other, it would be down to two and even MORE unbalanced)</span>
Q=mc(deltaT)
Q is the amount of energy which you are looking for
M is the mass which you can find
C is the specific heat of water which is 4.18 J/gC
DeltaT is the change in temperature which you can find.
To find the mass, first you must know that the density of water is 1g/mL, meaning that 200 mL has a mass of 200 g. This means that to find the total mass (m in the equation) all you need to do is add the mass of water and NaOH.
200 g + 2.535 g=202.535 g.
To find deltaT you would need to take the final temperature minus the initial temperature.
27.8C-24.2C=3.6C
Then these values can be substituted into the equation:
q=(202.635g)(4.18J/gC)(3.6C)
Q=3049.25 J
Technically this should be rounded off to 1 significant figure (200 mL only had 1), but ignoring signficiant figure rules this should be correct. Also, sometimes other units like calories or kJ may be asked for, meaning that a conversion or alternate c value would be used.
The percent error associated with Jason’s measurement is 0.596%.
HOW TO CALCULATE PERCENTAGE ERROR:
- The percentage error of a measurement can be calculated by following the following process:
- Find the difference between the true value and the measured value of a quantity.
- Then, divide by the true value and then multiplied by 100
- The true value of the density of iron is 7.874 g/mL
- Jason observed value is 7.921 g/mL
Difference = 7.921 g/mL - 7.874 g/mL
Difference = 0.047 g/mL
Percentage error = 0.047/7.874 × 100
Percentage error = 0.596%.
Therefore, the percent error associated with Jason’s measurement is 0.596%.
Learn more: brainly.com/question/18074661?referrer=searchResults
Electrolyte for the electrolysis is copper(II) sulfate
CuSO₄ = Cu²⁺ + SO₄²⁻
the reaction at the negative electrode
(cathode -) Cu²⁺ + 2e⁻ = Cu⁰
and...
(anode +) 2H₂O - 4e⁻ = O₂ + 4H⁺
Answer:
liquid will be evaporated while solid remains
