Question

What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each question mark with the appropriate integer or symbol.

Answer 1

Answer: The daughter nuclide formed by the beta decay of given isotope is $_{30}^{64}\textrm{Zn}$

Explanation:

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

We are given:

Parent isotope = $_{29}^{64}\textrm{Cu}$

The chemical equation for the beta decay process of $_{29}^{64}\textrm{Cu}$ follows:

$_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta$

Hence, the daughter nuclide formed by the beta decay of given isotope is $_{30}^{64}\textrm{Zn}$