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3 years ago

What’s needed to build a neutral atom?

Chemistry

1 answer:

sdas [7]3 years ago

7 0

Answer:

Protons are positively charged, electrons are negatively charged (with the same magnitude of charge per particle as a proton). Neutrons have no charge. Now, in a "neutral atom", the number of protons must be equal to the number of electrons, otherwise it would not be neutral.

Explanation:

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Is carbon dioxide a pure substance

iVinArrow [24]

Answer:

It is not a pure substance.

6 0

3 years ago

Why is sodium chloride not considered a molecular compound? What kind of compound is it?

e-lub [12.9K]

Answer:

Something like table salt (NaCl) is a compound because it is made from more than one kind of element (sodium and chlorine), but it is not a molecule because the bond that holds NaCl together is an ionic bond. If you like, you can say that sodium chloride is an ionic compound.

Explanation:

5 0

2 years ago

Which of the following does not form a diatomic molecule?

Murrr4er [49]

<span>The correct answer among the choices given is option D. Copper does not form a diatomic molecule. A diatomic molecule has only two atoms. Diatomic molecules are molecule that are composed of two same atoms which are bonded covalently. An example are oxygen, it exist as O2 and chlorine, it exist as Cl2.</span>

7 0

4 years ago

Read 2 more answers

A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder

Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

$PV_1=nRT$

where,

P = pressure of gas = 1 atm

$V_1$ = volume of gas = ?

T = temperature of gas = $270^oC=273+270=543K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K$

$V_1=9.12L$

Now we have to calculate the volume at 24°C.

$PV_2=nRT$

where,

P = pressure of gas = 1 atm

$V_2$ = volume of gas = ?

T = temperature of gas = $24^oC=273+24=297K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K$

$V_2=4.99L$

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 9.12 L

$V_2$ = final volume = 4.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (4.99-9.12)L$

$w=4.13L.artm=4.13\times 101.3J=418.4J$

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0

3 years ago

A substance with a density of 2.70 g/mL occupies a volume of 21.3 mL. What is the mass of the sample? Report your answer in unit

katen-ka-za [31]

We know the formula of the density:
ρ = $\frac{m}{V}$ ;
So the mass will be equal to:
m = ρ * V = 2.70 * 21.3 = 57,51 g = 57510 mg of substance.
So the answer is 57510.

7 0

3 years ago