In a function, each domain element can have at most one range element. So we'll have to remove one of the links from 3. Either one can be removed, since it is OK for two domain elements to map to the same range element (as is the case for 3->b and 4->b).
This is all very theoretical, but here is a real life example.
Take f(x) = x²
You probably know that both f(2) and f(-2) is 4.
There 2 and -2 are in the domain, 4 is in the range.
Answer:
the number of sponges per package bought be 32.5
Step-by-step explanation:
Let us assume the number of sponges per package be x
So the number of packages he bought be x - 14
And, the overall he bought 51 sponges
So
the number of packages of sponges did roger buy is
x + x - 14 = 51
2x = 51 + 14
2x = 65
x = 32.5
So the number of sponges per package bought be 32.5
If we start with 6 and 8, we can break 6 up into 2*3 and 8 into 2*2*2, thus getting a prime factorization of 2*2*2*2*3, or 2^4 *3.
If we begin with 4 and 12, 4 breaks into 2*2 and 12 into 2*2*3, so the prime factorization of 48 is still 2^4 *3.
The starting factors do not matter, since the answer comes out to be the same. There is exactly one correct answer- it doesn't matter how it's found.
Hope this helps! :)
