(20 POINTS AND BRAINLIEST FOR BEST)

Emma has 4 baskets. She wants to put 5 apples in

statuscvo [17]

Answer:

17

Step-by-step explanation:

4x5=20 20 - 3= 17

5 0

3 years ago

Read 2 more answers

Carys is checking her tax bill for the last year.

AfilCa [17]

Answer:

$7,440.

Step-by-step explanation:

$0-$11,000 = no tax.

$11,000-$43,000 = 20%.

$43,000-$150,000 = 40%.

The earnings over $150,000 = 45%. etc....

$45,600, = Revenue

Tax is 11000-43000 is = 0.20 * (32000)

= 11000-43000 = 6400

Tax is 43000-45,600 is = 0.40 *(2600)

= 45,600-43000 = 1040

=6400+1040 =7440

3 0

4 years ago

E

IgorLugansk [536]

Answer:

10.35 miles in 1 hout

Step-by-step explanation:

I'm Sorry if this wrong.

5 0

3 years ago

Based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age

svetoff [14.1K]

Answer:

We conclude that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company.

Step-by-step explanation:

We are given that based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age of 25.

A random sample of 52 claims showed that 43 were made by single people under the age of 25.

Let p = population proportion of claims made by single people

So, Null Hypothesis, $H_0$ : p $\leq$ 67% {means that the insurance claims of single people under the age of 25 is smaller than or equal to the national percent reported by the large insurance company}

Alternate Hypothesis, $H_A$ : p > 67% {means that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of claims made by single people under the age of 25 = $\frac{43}{52}$ = 0.83

n = sample of claims = 52

So, the test statistics = $\frac{0.83-0.67}{\sqrt{\frac{0.67(1-0.67)}{52} } }$

= 2.454

The value of z-test statistics is 2.454.

Since in the question, we are not given the level of significance so we assume it to be 5%. Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 2.454 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company.

6 0

4 years ago

Can You Help Me With This:

lapo4ka [179]

Answer:

Here the given table,

Outcomes Red yellow blue Misses

Frequency 10 35 48 7

$\text{Relative frequency of a event} = \frac{\text{Frequency of that event}}{\text{Sample size}}$