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SashulF [63]
3 years ago
12

PLEASE HELP EXPLAIN IT TO ME HOW TO DO THIS I AM BEGGING

Mathematics
1 answer:
Anarel [89]3 years ago
7 0
1 1/2 -2 1/4 will give you the rule
I it helps
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Please help, I need it due today and urgently! Please give a small explanation and an answer
Lana71 [14]

Answer:

0=0 1=1   <u> 6<8</u>

Since 6 < 8  0.16 < 0.18

so, the hummingbird weighs more than a nickel

Step-by-step explanation:

6 is less than 8 so therefore .16 is less than .18. The nickel weighs .18 and .16 is less than that.

8 0
3 years ago
Help, I don’t understand the problem I tried but I keep getting the wrong answer
Eddi Din [679]
It’s too blurry
Make picture clearer
4 0
3 years ago
The angle between a 180-pound force F and AB= 5i + 2j is 30.Find the work done by F in moving and object from A to B.
Alexeev081 [22]

Answer:

W=839.464\ ft*lbf

Step-by-step explanation:

The work done is the product of the magnitude of the force applied to the object by the magnitude of the displacement of the object by the cosine of the angle between the force and direction of the displacement. This is:

W=|F|*|r|cos(\theta)

In this case

\theta=30\°

|F|=180 pound force

The magnitude of vector AB is:

|r|= \sqrt{5^2 + 2^2}\\\\|r|= \sqrt{29}\ fr

Finally the work is:

W=180*\sqrt{29}*cos(30\°)

W=839.464\ ft*lbf

6 0
3 years ago
Read 2 more answers
If anyone's good with interquartile range, median, upper quartile, lower quartile stuff, please help ASAP!
kramer

Answer: B, Range is 16, IQR is 7

Step-by-step explanation:

Quartiles:

Quartiles mark each 25% of a set of data:

The first quartile Q1 is the 25th percentile

The second quartile Q2 is the 50th percentile

The third quartile Q3 is the 75th percentile

The second quartile Q2 is easy to find. It is the median of any data set and it divides an ordered data set into upper and lower halves. The first quartile Q1 is the median of the lower half not including the value of Q2. The third quartile Q3 is the median of the upper half not including the value of Q2.

How to Calculate Quartiles:

Order your data set from lowest to highest values

Find the median. This is the second quartile Q2.

At Q2 split the ordered data set into two halves.

The lower quartile Q1 is the median of the lower half of the data.

The upper quartile Q3 is the median of the upper half of the data.

If the size of the data set is odd, do not include the median when finding the first and third quartiles. If the size of the data set is even, the median is the average of the middle 2 values in the data set. Add those 2 values, and then divide by 2. The median splits the data set into lower and upper halves and is the value of the second quartile Q2.

How to Find Interquartile Range

The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum:

The minimum is the smallest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=x1=min(xi)ni=1

How to Find the Maximum:

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn.

3 0
2 years ago
Of the 800 particapants in a marthon, 120 are running to raise money for a cause. How many particpants out of 100 are running fo
stiv31 [10]

Answer:

15

Step-by-step explanation:

800/8 = 100

sooo.......

120/8 = 15

15/100

hope this helps ! :)

3 0
3 years ago
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