The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
1 / 8 = x / 56
cross multiply
8x = 56
x = 56/8
x = 7 eggs are needed to make 56 slices
The statistical question would be “what are the ages of all your cousins?”
Hope this helped <3
Answer:
you set them to equal each other so you are able to get all the variables in the same way since sometimes being on one side of the equal can make it positive but on the other side it would be negative
Answer:
The solution of the first image is: b = √48
The solution of the second image is: c = √125
Step-by-step explanation:
Here we have two triangle rectangles, first, we need to remember the Pythagorean theorem.
For a triangle rectangle with cathetus A and B, and a hypotenuse H, we have the relationship:
A^2 + B^2 = H^2
Where H is the side that is opposite to the right angle (the angle of 90°)
In the first image, we can see that the hypotenuse is equal to 8, and one cathetus is equal to 4.
We want to find the value of b, that is the other cathetus.
Then we have:
4^2 + b^2 = 8^2
b^2 = 8^2 - 4^2
b^2 = 48
b = √48
Second image:
in this case, c is the hypotenuse, a and b are the cathetus.
We know that:
a = 5, b = 10
Then we have the equation:
a^2 + b^2 = c^2
Now we can replace the above values:
5^2 + 10^2 = c^2
25 + 100 = c^2
125 = c^2
√125 = c
