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iragen [17]
3 years ago
11

Find the perimeter of the shaded region

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

13 u²

Step-by-step explanation:

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Perform the operations and write the answer in simplest form 2 2/5 + 3 1/4
iragen [17]

Answer: 2 2/3


Step-by-step explanation:

we have to turn this into a improper fractions first (so its something like a bobble-head)

(2 2/5) 5 x 2 = 10 + 2 = 11/5

(3 1/4) 3 x 4 = 12 + 1 = 13/4

Then add those two.

11/5 + 13/4

11 + 13 = 24

5 + 4 = 9

 so now its time to put it in simplest form 8/3

Now 8 divided by 3...BUT WAIT...3 can't go into 8

Now we turn it into a Mixed Number 2 2/3

5 0
3 years ago
You are applying for jobs at two companies. Company A offers starting salaries with μ = $41,000 and σ = $1,000. Company B offers
NeTakaya
Company B po



Ang sagot


Tamang tama po iyan



B po ang sagot
4 0
3 years ago
Consider the function below. f(x) = 6x tan x, −π/2 < x < π/2 (a) find the vertical asymptote(s). (enter your answers as a
Molodets [167]

Answer: Does not exist.

Step-by-step explanation:

Since, given function,  f(x) = 6x tan x, where −π/2 < x < π/2.

⇒ f(x) = \frac{6x sin x}{cosx}

And, for vertical asymptote,  cosx= 0

⇒ x = π/2 + nπ where n is any integer.

But, for any n x is does not exist in the interval ( -π/2, π/2)

Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.


5 0
3 years ago
Read 2 more answers
How do you solve this?
DiKsa [7]

Triangles ABC and LBM are similar. We know this because AL and LB have the same length, so that AB is twice as long as either AL or LB. The same goes for MC and BM, and BC. The angle B is the same for both tirangles ABC and LBM, so the side-angle-side postulate tells us the triangles are similar, and in particular that triangle ABC is twice as large as LBM.

All this to say that LM must be half as long as AC, so LM has length (B) 14 cm.

3 0
3 years ago
-3x + 7y = -1<br> - 2x + 5y=0
Talja [164]
(X,Y) = (9/13 , 2/13)
6 0
3 years ago
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