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2 years ago

I really need help with my test ill do anything plzz

Mathematics

1 answer:

lesantik [10]2 years ago

4 0

Answer:

Step-by-step explanation:

All the other points seem to be present on the graph

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What is the unit price for trail mix if a 8 ounce bag cost $2.80.

german

Answer:

Step-by-step explanation:

2.80/8=.35 per ounce

6 0

2 years ago

The cost of a computer is $849. The store is offering a 20% discount, and then a sales tax of 6% is added after the discount. WH

Alex_Xolod [135]

Answer:

$719.95

Step-by-step explanation:

To find the purchase total, multiply the price by the percent paid and add the percent of tax.

The store offers a 20% discount. This means you pay 80% of the price. So the discounted price is 0.80(849) = 679.2.

Find the tax to be paid by multiplying 0.06(679.2) = 40.752.

Add the tax for the final total.

679.2 + 40.752 = 719.95

3 0

3 years ago

Work out the mean. 1, 3, 3. 4. 6, 9, 9

I am Lyosha [343]

1+3+3+4+6+9+9 is 35
7 numbers so divide by 7
35/7 = 5
Mean is 5

8 0

2 years ago

Read 2 more answers

School a rented 1 van and 3 buses with 89 students. School b rented 4vans and 3 buses with. 131 students. Each van and each bus

iogann1982 [59]

Answer:18

Step-by-step explanation:

3 0

2 years ago

Y=-x^2+6x-4 Find the Axis of Symmetry and the Vertex, Also solve the whole equation.

Inessa [10]

Answer:

1. Axis of symmetry: x = 3

2. Vertex: (3,5)

3. Solution of the equation:

x-intercepts:

$(3-\sqrt{5},0) \\\\(3+\sqrt{5},0)$

y-intercept: (0, -4)

Explanation:

1. Equation:

$y=-x^2+6x-4$

2. Axis of symmetry:

That is the equation of a parabola, whose standard form is:

$y=ax^2+bx+c$

Where:

$a=-1;b=6;c=-4$

The axis of symmetry is the vertical line with equation:

$x=-b/2a$

Substitute $a=-1,\text{ and }b=6$

$x=-6/[(2)(-1)]=-6/(-2)=3$

Thus, the axis of symmetry is:

$x=3$

3. Vertex

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

$y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5$

Therefore, the vertex is (3, 5)

4. Find the x-intercepts

The x-intercepts are the roots of the equation, which are the points wher y = 0.

$y=-x^2+6x-4=0$

Use the quadratic equation:

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}$

5. Find the y-intercept

The y-intercet is the value of y when x=0:

$y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4$

7 0

3 years ago