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3 years ago

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Lauren drove The 75 miles to the coast at 75 mph, but gets stuck in traffic and averaged 25 mph on the way back. How many total

miles did Lauren Drive in this round trip

1 answer:

aksik [14]3 years ago

8 0

Answer:

150 miles

Step-by-step explanation:

In this problem, we are only interested in the distance that Lauren drove, this means that her average speed (75 mph to the cost, and 25 mph on the way back) does not matter since the distance remains the same. If one leg of trip is 75 miles long, the total mileage for the round trip is:

$M=75+75\\M=150\ miles$

Lauren drove 150 miles.

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Anettt [7]

Answer: A) 5m = 50; m = 10

Step-by-step explanation:

The diagram shows 5 "m"s, or 5*m equal to 50. Thus, 5m=50.

Because 5m = 50, divide both sides by 5 to get that m = 10

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2 years ago

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Find the area of a triangle with legs that are 9mm 6mm and 12mm

Sidana [21]

Here we are given the three sides of the triangle.

So we have Heron's formula to find its area.

Heron's formula is given by :

$A= \sqrt{S(S-A)(S-B)(S-C)}$

where A, B and C are sides of triangle and S is semi perimeter which is given by,

$S= \frac{A+B+C}{2}$

plugging values of A, B and C to find S

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S=13.5

Now plugging values of A, B , C and S in Heron's formula

$A= \sqrt{13.5(13.5-9)(13.5-6)(13.5-12)}$

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2 years ago

Graph the solution of the inequality. v−4≥−9

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2 years ago

A devastating freeze in California's Central Valley in January 2007 wiped out approximately 75% of the state's citrus crop. It t

solniwko [45]

The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

<em>The linear equation of the function is: </em> $g(P) = 22.9P+7$ <em>.</em>
<em>The inverse function is: </em> $g^{-1}(c) = \frac{1}{22.9}(c - 7)$ <em> .</em>
<em>A practical domain is from 0% to 100%</em>
<em>A practical range is from 7 to 29.9 </em>

<u>A. Input quantity</u>

The input quantity is the percentage of frozen citrus crop

<u />

<u>B. Output quantity </u>

The output quantity is the cost of box of oranges

<u>C. The linear function</u>

We have:

$(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)$

<em>Calculate the slope of the function</em>

$m = \frac{c_2 - c_1}{P_2 - P_1}$

$m = \frac{25.32 - 11.58}{80\%-20\%}$

$m = \frac{13.74}{60\%}$

$m = 22.9$

<em>The linear equation is calculated as follows:</em>

$c -c_1 = m(P-P_1)$

$c -11.58= 22.9(P-20\%)$

$c-11.58 = 22.9P-4.58$

<u>D. Rewrite as y = mx + b</u>

We have:

$c-11.58 = 22.9P-4.58$

Collect like terms

$c = 22.9P - 4.58 + 11.58$

$c = 22.9P+7$

<em>The function is:</em>

$g(P) = 22.9P+7$

<u>E. A practical domain</u>

The domain is the possible values of P. Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: $[0\%,100\%]$

<u>F. A practical range</u>

When P = 0%

$c = 22.9 \times 0\% + 7 = 7$

When P = 100%

$c = 22.9 \times 100\% + 7 = 29.9$

Hence, the range of the function is: $[7,29.9]$

G. The meaning of $g^{-1}(12)$

The inverse function of g(P) is $g^{-1}(P)$

So:

$g^{-1}(12)$ is the percentage of frozen citrus crop, when the cost is $12.

<u>H. The inverse formula</u>

We have:

$c = 22.9P+7$

Subtract 7 from both sides

$c - 7 = 22.9P$

Make P the subject

$P = \frac{1}{22.9}(c - 7)$

So, the inverse formula is:

$g^{-1}(c) = \frac{1}{22.9}(c - 7)$

Substitute 12 for c

$g^{-1}(12) = \frac{1}{22.9}(12 - 7)$

$g^{-1}(12) = \frac{1}{22.9} \times 5$

$g^{-1}(12) = 22\%$

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