Simplify 11 to the power of negative 4 over 11 to the power of 8
1 answer:
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Answer:
The coordinates of the intersection of the medians of △ABC is (1/3, 1).
Step-by-step explanation:
Consider the vertices of △ABC are A(2, 4), B(−4, 0), and C(3, −1).
Intersection of the medians of a triangle is known as centroid.
Formula for centroid of a triangle is
Using the above formula the centroid of △ABC is
Therefore the coordinates of the intersection of the medians of △ABC is (1/3, 1).
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The first step is to get rid of those very large numbers. It's going to be very difficult to factor unless we can bring those high numbers down. So lets see if we can factor each term.
So after dividing 49 with every single digit. The only number that divides evenly is 7 and one, and 16 isnt divisible evenly by 7 so that didn't work. Looks like we're gonna have to work with these big numbers.
There is something interesting though about these numbers. 16 and 49 are both perfect squares. 16 is the same as 4^2 and 49 is the same as 7^2. So we can factor the whole trinomial as:
If we were to expand this out as:
and multiply it back into the original form. It would match with the expression we started with. The 4's would multiply back into 16x^2 and the 7's would multiply back into 49.
Additionally 4 * -7 is -28, so you can combine two -28x's into the -56x term in the original trinomial.
Thus, the answer is yes you can, and the answer is: