Answer:
First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89 Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.
Step-by-step explanation:
Answer:
$5.5
Step-by-step explanation:
6 * N (notebook) + 3 * P (pen) = 27
n = 1.5 +P
6 * (1.5 + P) + 3 * P = 27
9 +6p +3p = 27
9p = 18
p (pen): $2
N (notebook): $3.5
combined cost of 1 pen and 1 notebook: $2 + $ 3.5 = $ 5.5
Yes and second no it is not
Answer: 
Step-by-step explanation:
I assume that you need the new coordinates of the point after the rotation centered at the origin.
For this exercise it is important to remember the definition of "Rotation".
A Rotation is defined as a transformation which a figure is rotated about a fixed point known as "Center of rotation".
The figure before the transformation is called Pre-Image and the figure obtained after the transformation is called "Image".
The 180 degree rotation about the origin Rule states that:
→ 
Therefore, knowing that the given point (5,4) is rotated 180 degrees clockwise about the origin, you can conclude that its Image is:
