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zhenek [66]
3 years ago
8

What is it??!!!!!??!??!?

Chemistry
1 answer:
Softa [21]3 years ago
4 0

Answer:

other the effect of temperature on plants

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The atomic theory has been revised many times over the last several hundred years. John Dalton described the atom as a solid sph
frez [133]
<span>As new discoveries are made, existing theories are revised or replaced.</span>
6 0
3 years ago
Read 2 more answers
The main type of attractive forces between molecules of carbon tetrabromide (cbr4) are:_______
romanna [79]

Answer:

Vanderwaals forces

Explanation:

CBr4 is a nonpolar molecule, nonpolar molecules usually possess vanderwaals forces between their molecules as their main attractive force.

CBr4 is nonpolar because the tetrahedral arrangement of the C-Br bonds cancel out the individual dipole moments of each C-Br bond thereby making the compound nonpolar, hence the answer above.

8 0
3 years ago
Plz Help Me
Rasek [7]

Answer:- The wavelength is 1.36*10^1^2m and the right option is D.

Solution:-  Wavelength is inversely proportional to the frequency and the equation is:

\lambda =\frac{c}{\nu }

where, \lambda&#10; is the wavelength, c is the speed of light and \nu is frequency.

Frequency is 2.20*10^-^4Hz and the speed of light is 3.00*10^8\frac{m}{s} .

Since, 1Hz=1s^-^1

So, 2.20*10^-^4Hz=2.20*10^-^4s^-^1

Let's plug in the values in the equation:

\lambda =\frac{3.00*10^8m.s^-^1}{2.20*10^-^4s^-^1}

\lambda =1.36*10^1^2m

Hence, the right option is D) 1.36*10^1^2m .





7 0
4 years ago
Read 2 more answers
Pls help i am in 8th grade k12
zheka24 [161]
It’s definitely persuade!
4 0
2 years ago
what is the specific heat of a 25.0 g substance that absorbs 493.4 j and raises the temperature from 12.0°c to 34°c?​
stellarik [79]

Answer:

Specific heat of substance  = 0.897 J/g.°C

Explanation:

Given data:

Specific heat of substance = ?

Mass of substance = 25.0 g

Heat absorbed = 493.4 J

Initial temperature = 12.0 °C

Final temperature = 34°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 34°C -12.0°C

ΔT = 22°C

493.4 J  = 25 g ×c× 22°C

493.4 J  = 550 g.°C ×c

c = 493.4 J  / 550 g.°C

c = 0.897 J/g.°C

4 0
3 years ago
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