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julia-pushkina [17]
3 years ago
5

Which statement describes an intensive property of matter? ​

Chemistry
2 answers:
ANEK [815]3 years ago
6 0
An intensive property is a property of matter that depends only on the type of matter in a sample and not on the amount. Other intensive properties include color, temperature, density, and solubility.
Pachacha [2.7K]3 years ago
5 0

Answer:

hope it helped you.

Explanation:

The properties of matter that do not depend on the size or quantity of matter in any way are referred to as an intensive property of matter. Temperatures, density, color, melting and boiling point, etc., all are intensive property as they will not change with a change in size or quantity of matter.

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What is the concentration of a solution of HBr if 0.40 L is neutralized by 0.20 L of 0.50M solution of LiOH?
marysya [2.9K]
Since the mole ratio is 1 to 1 for this reaction, you can just use M1V1 = M2V2 to solve, given that 1 refers to HBr and 2 refers to LiOH.

M1 = ?
V1 = 0.40 L
M2 = 0.50 M
V2 = 0.20 L

M1(0.40) = (0.50)(0.20)

Solve for M1 —> M1 = (0.50)(0.20)/0.40 = 0.25 M HBr
4 0
3 years ago
Do anyone know how to do question B
Over [174]

Answer:

a) IUPAC Names:

                   1) (<em>trans</em>)-but-2-ene

                   2) (<em>cis</em>)-but-2-ene

                   3) but-1-ene

b) Balance Equation:

                       C₄H₁₀O + H₃PO₄   →   C₄H₈ + H₂O + H₃PO₄

As H₃PO₄ is catalyst and remains unchanged so we can also write as,

                                    C₄H₁₀O   →   C₄H₈ + H₂O

c) Rule:

           When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.

d) C is not Geometrical Isomer:

        For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.

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Explanation:
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Irina-Kira [14]

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