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Slav-nsk [51]
3 years ago
5

A car sitting at rest begins

Physics
1 answer:
tamaranim1 [39]3 years ago
5 0

Answer:

It's 2km

Explanation:

a=2.40

T=15s

Speed=2.40*15

//. =36km/h

Distance=S*T

//. =36*15

//. =540m

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A charge q1 of -5.00X10^-9 C and a charge q2 of -2.00X10^-9 C are separated by a distance of 40.0 cm. Find the equilibrium posit
Alex73 [517]

Answer:

The equilibrium position for the third charge is 69.28 cm

Explanation:

Given;

q₁ = -5.00 x 10⁻⁹ C

q₂ = -2.00 x 10⁻⁹ C

q₃ = 15.00 x 10⁻⁹ C

distance between q₁  and q₂ = 40.0 cm = 0.4 m                                    

(-q₁)--------------------------------------(-q₂)---------------------------------(+q₃)

At equilibrium the repulsive force between q₁ and q₂ must be equal to attractive force between q₂ and q₃

According to Coulomb's law, repulsive or attractive force between charges is calculated as;

F = \frac{Kq_1q_2}{r_1^2} =  \frac{Kq_2q_3}{r_2^2}

where;

F is repulsive or attractive force between charges

K is Coulomb's constant = 8.99 x 10⁹ Nm²/c²

r₁ is the distance between q₁ and q₂

q₁, q₂ and q₃ are the charge

distance between q₂ and q₃, r₂ is calculated as;

\frac{Kq_1q_2}{r_1^2} = \frac{Kq_2q_3}{r_2^2}\\\\\frac{q_1q_2}{r_1^2} = \frac{q_2q_3}{r_2^2}\\\\r_2^2= \frac{r_1^2q_2q_3}{q_1q_2}\\\\r_2^2= \frac{r_1^2q_3}{q_1} = \frac{0.4^2*15*10^{-9}}{5*10^{-9}} = 0.48\\\\r_2 = \sqrt{0.48} = 0.6928 \ m

Therefore, the equilibrium position for the third charge is 69.28 cm

3 0
3 years ago
If you increase the frequency what happens to the distance between the waves (wavelength)?
Dahasolnce [82]

Answer:

C)the distance decreases Shorter wavelength

Step by step Explanation:

5 0
3 years ago
A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is 5) its radius? (The value of o is 4 ×
Elan Coil [88]
The self-inductance of a solenoid is given by:
L= \frac{\mu_0 N^2 A}{l}
where
\mu_0 is the vacuum permeability
N is the number of turns
A is the cross-sectional area of the solenoid
l is the length of the solenoid

For the solenoid in our problem, N=3000, l=70.0 cm=0.70 m and the self-inductance is L=25.0 mH=0.025 H, therefore the cross-sectional area is
A= \frac{Ll}{\mu N^2}= \frac{(0.025 H)(0.70 m)}{(4\pi \cdot 10^{-7}N/A^2)(3000)^2}= 1.55 \cdot 10^{-3}m^2
And since the area is related to the radius by
A=\pi r^2
The radius of the solenoid is
r= \sqrt{ \frac{A}{\pi} } = \sqrt{ \frac{1.55 \cdot 10^{-3} m^2}{\pi} } =0.022 m=2.2 cm

6 0
3 years ago
What causes differences in air pressure around the Earth?
Olegator [25]
Wind is primarily driven by differences in air pressure. These variations in air pressure are due to temperature differences caused by variations in solar energy received at the surface of the Earth.
7 0
4 years ago
What are the uses of nuclear fission or fusion and their benefits
tamaranim1 [39]

Answer: The uses of nuclear fission are nuclear activator utilize for mercantile electric-power alternator throughout the world and it also has powerful starting point for propelling submarines and certainly kinds of surface yacht. And about the fusion benefits, that is that the nuclear fusion has clean vigor, very low power source cost, along with other benefits.

Hopefully this helps you my dear friend! :-)

6 0
4 years ago
Read 2 more answers
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