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ziro4ka [17]
3 years ago
6

What causes differences in air pressure around the Earth?

Physics
1 answer:
Olegator [25]3 years ago
7 0
Wind is primarily driven by differences in air pressure. These variations in air pressure are due to temperature differences caused by variations in solar energy received at the surface of the Earth.
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Does peer pressure affect your physical activity routine? Describe this peer pressure and tell whether it is positive or negativ
Alexxx [7]
Yes, peer pressure affects one's physical activity routine. It can do so both negatively and positively. For instance, if one is pressured to do drugs when around their peers, it would most likely lead to an addiction that lasts even when they are not with those people anymore. However, from a positive viewpoint, one's peers could also pressure them to do something productive, such as trying a new beneficial activity that they are afraid of (ex. trying out for a talent show.) This could lead to a disruption in routine as that individual would begin practicing for said talent show. Hence, peer pressure can be both negative and positive, but in both instances, it changes the routine of the individual effected. 
4 0
3 years ago
Read 2 more answers
A light source radiates 60.0 W of single-wavelength sinusoidal light uniformly in all directions. What is the amplitude of the m
Anna35 [415]

To solve this problem it is necessary to take into account the concepts of Intensity as a function of Power and the definition of magnetic field.

The intensity depending on the power is defined as

I = \frac{P}{4\pi r^2},

Where

P = Power

r = Radius

Replacing the values that we have,

I = \frac{60}{(4*\pi (0.7)^2)}

I = 9.75 Watt/m^2

The definition of intensity tells us that,

I = \frac{1}{2}\frac{B_o^2 c}{\mu}

Where,

B_0 =Magnetic field

\mu = Permeability constant

c = Speed velocity

Then replacing with our values we have,

9.75 = \frac{Bo^2 (3*10^8)}{(4\pi*10^{-7})}

Re-arrange to find the magnetic Field B_0

B_o = 2.86*10^{-7} T

Therefore the amplitude of the magnetic field of this light is B_o = 2.86*10^{-7} T

6 0
3 years ago
A horizontal force in used to pull a 5 kilogram cart at a constant speed of 5 meters per second across the floor as shown in the
ddd [48]

A cart is pulled by horizontal force such that it moves with constant velocity

So here since velocity is constant we can say that its acceleration will be ZERO

now here for zero acceleration we can say

F_{net} = 0

So here we will have

F_{net} = F_{ap} - F_f = 0

here we know that

F_f = 10 N

so we will have

F_{ap} - 10 = 0

F_{ap} = 10 N

so here applied force on handle will be

<em>b. 10 N</em>

5 0
3 years ago
I need the answer a sap please
pogonyaev
D is the answer
I hope it helps!
7 0
3 years ago
Arm
Daniel [21]
Can't say for sure but I think it's a) or c)
3 0
3 years ago
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