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shepuryov [24]
3 years ago
7

9. Luke is an astronaut that moves his position in the space shuttle by climbing a

Physics
2 answers:
BartSMP [9]3 years ago
6 0

Explanation:

Remember that power is defined as how much Work is done per unit of time.

P = \frac{dW}{dt}

Work is defined as the amount of force applied across a certain distance.  

W = F*d

Since in both cases of climbing the ladder (on Earth and the moon), Luke coveres the same amount of <em>distance </em>in the same amount of <em>time</em>, we are only left with one difference between the two cases - gravity.

If you were to carry your backpack on the moon with the same load of text books, it would take less force to pick it up on the moon. Therefore, Luke expends less effort on the environment with less gravity - the moon.

To find the difference factor - you would want to divid the gravitational contants between earth and the moon.

ludmilkaskok [199]3 years ago
4 0

Answer:

It takes 6.125 times as much work on Earth as it does on the moon.

Explanation:

Formulas

The power formula is

P = Work / Time

Work = Force * distance

Givens

d = 3.0 meters

t = 5.0 seconds

g = 9.8 m/s^2 on earth

g = 1.8 m/s^2 on the moon

Solution

<u>Earth</u>

Work  = F * d

Work = m* a * 3.0 m

Work = m *9.8 * 3.0

Work = m * 29.4

Power = (Work * 29.4)/5

Power = 29.4/5 * m

Power = 5.88 watts.

<u>Moon</u>

You follow the same procedure except you use 1.6 for a.

Work = m * 1.6 * 3

Work = 4.8*m Joules

Power = 4.8 * m/ 5

Power = 0.96 * m Watts

P_earth/Power_moon = 5.88 * m / 0.96 * m = 6.125

Power =

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Answer:

B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C

Explanation:

From Coulomb's Law the electrostatic repulsive force is given by the following formula:

F = kq₁q₂/r²

where,

F = Repulsive Force = 0.15 N

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = Magnitude of 1st Charge = ?

q₂ = Magnitude of 2nd Charge = ?

r = Distance between Charges = 0.5 m

Therefore,

0.15 N = (9 x 10⁹ N.m²/C²)q₁q₂/(0.5 m)²

q₁q₂ = (0.15 N)(0.5 m)²/(9 x 10⁹ N.m²/C²)

q₁q₂ = 4.17 x 10⁻¹²

q₁ = (4.17 x 10⁻¹²)/q₂   -------------------- equation (1)

The sum of charges is given as:

q₁ + q₂ = 8 μC

q₁ + q₂ = 8 x 10⁻⁶

using equation (1):

(4.17 x 10⁻¹²)/q₂ + q₂ = 8 x 10⁻⁶

(4.17 x 10⁻¹²) + q₂² = 8 x 10⁻⁶ q₂

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Solving this quadratic equation:

q₂ = 7.4 x 10⁻⁶ C   (OR)   q₂ = 0.56 x 10⁻⁶ C

q₂ = 7.4 μC   (OR)   q₂ = 0.6 μC

Therefore,

q₁ = (4.17 x 10⁻¹² C)/(7.4 x 10⁻⁶ C)

q₁ = 0.6μC

Now, if we solve with q₂ = 0.6 μC, we will get q₁ = 7.4 μC.

Therefore, the correct option will be:

<u>B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C</u>

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Verena is mixing a material into a beaker filled with a liquid. She notices that the material seems to disappear into the liquid
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She observes solubility - the ability of the substance to dissolve in e.g. the liquid.

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Q 29.1 a sheet of copper is placed between the poles of an electromagnet with the magnetic field perpendicular to the sheet. whe
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(a) The force required to remove the sheet increases with increase in speed due to change in magnetic flux.

(b) The area in the magnetic field changes as the sheet is being put in between the poles. Thus, a force would be required to put the sheets.

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When the sheet is pulled out, from the electromagnet there is change in magnetic flux given as follows;

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Thus, the force required to remove the sheet increases with increase in speed due to change in magnetic flux.

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Answer:

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