As stated in (i), the equation of the line is: ln y = -0.015x + .26
(By the way, I checked your answers for parts (i) and (ii) and they are both correct)
(iii)
Plug in (1.1) for y and solve:
ln (1.1) = -0.015x + .26
0.095 = -0.015x + .26
-0.165 = - 0.015x
10.979 = x
Answer: x = 10.979
Answer:
<u>slope=-2</u>
Step-by-step explanation:
Okay so we just take those coordinates and apply them to this formula:
y2-y1/x2-1
then simplify to get -2
if you want me to elaborate just say the word
In order to find the slope of a line parallel to this one, we must be familiar with the slope/intercept form, which is y= mx + b. M would be the slope. Therefore this line has a slope of 2. Parallel lines have the same slope, therefore<em> a line parallel to y=2x has a slope of </em><em>2</em><em>. </em>
Answer:
The mean score in the math test for class B=28.47
Step-by-step explanation:
<em>Step 1: Determine the total number of students in both Classes</em>
Total number of students=number in class A+number in class B
where;
number in class A=11 pupils
number in class B=15 pupils
replacing;
Total number of students=11+15=26 students
<em>Step 2: Determine total score for both classes</em>
Total score for both classes=total score for class A+total score for class B
total score for both classes=mean score for both classes×total number of students
total score for both classes=(49×26)=1,274
total score for class A=mean score for class A×total number of class A students
total score for class A=(77×11)=847
total score for class B=mean score for class B×total number of class B students
total score for class B=m×15=15 m
replacing;
1,274=847+15 m
15 m=1,274-847
15 m=427
m=427/15=28.47
The mean score in the math test for class B=28.47
