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Shkiper50 [21]
3 years ago
10

So what is 3.30 - 3.09 - 2.98

Mathematics
1 answer:
aalyn [17]3 years ago
6 0

Answer:

-2.77 is the correct answer (doing this to get to 20 characters lol)

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What is the length of the dotted line in the diagram below? Leave your answer in simplest radical form.
Pachacha [2.7K]

Answer:

\sqrt{93}

Step-by-step explanation:

8^2+5^2=c^2

64+25=c^2

89=c^2

c=\sqrt{89} <-- this is the length of the rectangle at the bottom

2^2+(\sqrt{89})^2=c^2

4+89=c^2

c=\sqrt{93}  <-- length of dotted line (diagonal)

6 0
2 years ago
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Several weeks ago an article appeared in the press comparing the Fit Bit exercise monitor to the Garmin monitor. In fact, earlie
MAXImum [283]

Answer:

thank you for replying

Step-by-step explanation:

thank you for replying

6 0
3 years ago
Use function notation to write the equation of the line.
malfutka [58]
The answer is c. See explanation below.

6 0
3 years ago
Write an equation in slope-intercept form for the following line:<br><br> (-14,1) and (13,-2)
alex41 [277]

Answer:

\large \boxed{y =  -  \frac{1}{9} x -  \frac{5}{9} }

Step-by-step explanation:

In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term is defined as slope in y = mx+b form which is slope-intercept form.

Now we substitute these ordered pairs (x, y) in the formula.

\large{m =  \frac{1 - ( - 2)}{ -14 - 13} } \\  \large{m =  \frac{1 + 2}{ - 27} } \\  \large{m =  \frac{3}{ - 27}  =  -  \frac{1}{9} }

After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is

\large \boxed{y = mx + b}

We already know m-value as we substitute it.

\large{y =  -  \frac{1}{9} x  + b}

We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)

We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.

\large{y = -  \frac{1}{9} x + b} \\  \large{ - 2 =  -  \frac{1}{9} (13) + b} \\  \large{ - 2 =  -  \frac{13}{9}  + b} \\  \large{ - 2 +  \frac{13}{9}  = b} \\  \large{ -  \frac{5}{9}  = b}

Finally, we know b-value. Then we substitute it in our equation.

\large{y =  -  \frac{1}{9} x + b} \\  \large{y =  -  \frac{1}{9} x -  \frac{5}{9} }

4 0
2 years ago
If triangle ABC defined by the coordinates A(1,1), B(9,1), C(1,9) is dilated by a scale factor of 1/2
alukav5142 [94]

Answer:

The transformed points of the triangle ABC are A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right), B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right), C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)

Step-by-step explanation:

The new points after applying the scale factor are, respectively:

A' (x,y) = \frac{1}{2}\cdot (1,1)

A' (x,y) = \left( \frac{1}{2}, \frac{1}{2}\right)

B' (x,y) = \frac{1}{2}\cdot (9,1)

B'(x,y) = \left(\frac{9}{2}, \frac{1}{2} \right)

C'(x,y) = \frac{1}{2}\cdot (1,9)

C'(x,y) = \left(\frac{1}{2}, \frac{9}{2}\right)

7 0
3 years ago
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