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ddd [48]
3 years ago
9

2 + 2 is 4, minus 1 that’s 3 quick maths

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

Step-by-step explanation:

is this a question

Alexeev081 [22]3 years ago
6 0
You are correct 4-1 does equal 3
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Taylor and Layla go to the movie theater and purchase refreshments for their friends.
zhenek [66]

The system of equations that can be used to find the price of one

drink and the price of one bag of popcorn is

4 x + 9 y = 43

2 x + 8 y = 25

The price of a drink is $8.50

Step-by-step explanation:

Taylor and Layla go to the movie theater and purchase refreshments

for their friends

  • Taylor spends a total of $43.00 on 4 drinks and 9 bags of popcorn
  • Layla spends a total of $25.00 on 2 drinks and 8 bags of popcorn

We need to write  a system of equations that can be used to find the

price of one drink and the price of one bag of popcorn

Assume that the price of each drink is $x and the price of each bag

of popcorn is $y

∵ Taylor spends a total of $43.00 on 4 drinks and 9 bags of popcorn

∴ 4 x + 9 y = 43 ⇒ (1)

∵ Layla spends a total of $25.00 on 2 drinks and 8 bags of popcorn

∴ 2 x + 8 y = 25 ⇒ (2)

The system of equations that can be used to find the price of one

drink and the price of one bag of popcorn is

4 x + 9 y = 43

2 x + 8 y = 25

Multiply equation (2) by -2 to eliminate x

∵ -2(2 x) + -2(8 y) = -2(25)

∴ -4 x - 16 y = -50 ⇒ (3)

- Add equations (1) and (3)

∴ -7 y = -7

- Divide both sides by -7

∴ y = 1

- Substitute y in equation (1) to find x

∵ 4 x + 9(1) = 43

∴ 4 x + 9 = 43

- Subtract 9 from both sides

∴ 4 x = 34

- Divide both sides by 4

∴ x = 8.5

∵ x is the price of each drink

∴ The price of a drink = $8.50

The price of a drink is $8.50

Learn more:

You can learn more about system of equation in brainly.com/question/6075514

#LearnwithBrainly

6 0
3 years ago
Find the slope of the line.
ladessa [460]
Lets take any two points on the line . I took (-2,-2) and (0,-3)
slope is rise/run = -3-(-2)/ 0-(-2) = -3+2/2= -1/2
answer is -1/2
4 0
3 years ago
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